我非常清楚 @SecondaryTable 注释是将单个实体的 字段映射到多个表 ,就好像这些表合并为一个表一样 我在实施这个概念时遇到了问题。 有3个类需要持久化,
Class1,其中4个中的2个字段将存储在其他2个不同的表中
@Entity
@Table(name = "MAIN_CAT")
@SecondaryTables({
@SecondaryTable(name = "CAT_1", pkJoinColumns = {
@PrimaryKeyJoinColumn(name = "CAT1_PK", referencedColumnName = "id")
}),
@SecondaryTable(name = "CAT_2", uniqueConstraints = {
@UniqueConstraint(columnNames = {"storyPart2"})
})
})
public class Cat {
@Id@GeneratedValue
private Long id;
private String catName;
@Column(table = "CAT_1")
private String storyPart1; // this field is going to be stored in CAT_1
@Column(table = "CAT_2")
private String storyPart2; // and so on
// getters and setters
}
第2课:持久化时此类将存储上述持久化类的storyPart1字段
@Entity
@Table(name = "CAT_1")
public class CatOne {
@Id
@GeneratedValue
@Column(name = "CAT1_PK")
private Long CAT1_PK;
@Column(name = "CATNAME_1")
private String catName1;
@Column(name = "CATAGE_1")
private String catAge1;
// getters and setters
}
第3课:持久化时此类将存储持久化Class 1的storyPart2字段
@Entity
@Table(name = "CAT_2")
public class CatTwo {
@Id
@GeneratedValue
private Long id;
@Column(name = "CATNAME_2")
private String catName2;
@Column(name = "CATAGE_2")
private String catAge2;
// getters and setters
}
数据库中创建的3个表是:
对于第1课:
CREATE TABLE main_cat
(
id bigint NOT NULL,
catname character varying(255),
CONSTRAINT main_cat_pkey PRIMARY KEY (id)
)
第2课:
CREATE TABLE cat_1
(
storypart1 character varying(255),
cat1_pk bigint NOT NULL,
catage_1 character varying(255),
catname_1 character varying(255),
CONSTRAINT cat_1_pkey PRIMARY KEY (cat1_pk),
CONSTRAINT fk_kvtvo6nrv78wxkm0kv01k9kdq FOREIGN KEY (cat1_pk)
REFERENCES main_cat (id) MATCH SIMPLE
ON UPDATE NO ACTION ON DELETE NO ACTION
)
对于第3课:
CREATE TABLE cat_2
(
storypart2 character varying(255),
id bigint NOT NULL,
catage_2 character varying(255),
catname_2 character varying(255),
CONSTRAINT cat_2_pkey PRIMARY KEY (id),
CONSTRAINT fk_2duj6ebg3504x18mlw2xkpvg6 FOREIGN KEY (id)
REFERENCES main_cat (id) MATCH SIMPLE
ON UPDATE NO ACTION ON DELETE NO ACTION,
CONSTRAINT uk_5ko8732qslvvx98gy0q666qrf UNIQUE (storypart2)
)
问题是,它不是在CAT_1中插入记录,而是为同一个触发2个插入。将记录插入CAT_2也会发生同样的事情。
Cat cat = new Cat();
cat.setCatName("CAT Name");
cat.setStoryPart1("STORYPART1");
cat.setStoryPart2("STORYPART2");
CatOne catOne = new CatOne();
catOne.setCatAge1("10");
catOne.setCatName1("catName1");
CatTwo catTwo = new CatTwo();
catTwo.setCatAge2("12");
catTwo.setCatName2("catName2");
session.save(cat);
session.save(catOne);
session.save(catTwo);
说明:
Hibernate: insert into CAT_1 (storyPart1, CAT1_PK) values (?, ?)
Hibernate: insert into CAT_1 (CATAGE_1, CATNAME_1, CAT1_PK) values (?, ?, ?)
由于将单个insert语句拆分为2语句,Hibernate会抛出此错误。
Caused by: org.postgresql.util.PSQLException: ERROR: insert or update
on table "cat_1" violates foreign key constraint
"fk_kvtvo6nrv78wxkm0kv01k9kdq" Detail: Key (cat1_pk)=(2) is not
present in table "main_cat".
看起来我以错误的方式实现了@SecondaryTable概念。在这种情况下如何使Hibernate触发单个插入?
答案 0 :(得分:2)
如果您已经将某个表用作实体的辅助表,那么将该表映射到另一个实体也不是一个好主意。辅助表应该被理解为给定实体的另一个表,它只能通过该实体进行管理。
如果您在辅助表上已有实体,则使用常规实体映射@OneToOne
,@ManyToOne
等。