Question

这是我的代码

//OnClick
Intent intent = new Intent(Intent.ACTION_PICK, ContactsContract.Contacts.CONTENT_URI);
startActivityForResult(intent, CONTACT_PICKER_RESULT);

@Override
public void onActivityResult(int reqCode, int resultCode, Intent data) {
    super.onActivityResult(reqCode, resultCode, data);

    switch (reqCode) {
        case (CONTACT_PICKER_RESULT) :
            if (resultCode == Activity.RESULT_OK) {
                Uri contactData = data.getData();
                Cursor c =  getActivity().getContentResolver().query(contactData, null, null, null, null);
                if (c.moveToFirst()) {
                    String name = c.getString(c.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
                    // TODO Whatever you want to do with the selected contact name.
                    Log.d("data",name);
                }
            }
            break;
    }
}

我在片段中使用它，它会打开联系人列表但是从不调用onActivityResult

Answer 1

由于声誉低，我可以写一个评论。检查manifest.xml中是否有以下标志：

android:launchMode="singleInstance"

或

android:noHistory="true"

因为它们无法提供结果。这些标志之间使用 <activity>代码

Answer 2

我在我的应用中使用了这种方法：首先为manifest.xml文件添加权限，如：

<uses-permission android:name="android.permission.READ_CONTACTS"/>

然后在想要向用户显示联系人时调用launchContactPicker（）：

public void launchContactPicker() {
    Intent contactPickerIntent = new Intent(Intent.ACTION_PICK,
            ContactsContract.Contacts.CONTENT_URI);
    startActivityForResult(contactPickerIntent, CONTACT_PICKER_RESULT);
}

然后在activityResult上添加：

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    // TODO Auto-generated method stub
        if(resultCode==RESULT_OK)
    {
        switch (requestCode) {
            case CONTACT_PICKER_RESULT:
                Cursor cursor;
                Bundle extras = data.getExtras();
                if(extras != null)
                {
                    Set<String> keys = extras.keySet();
                    for (String key : keys) {
                        extras.get(key);
                    }
                }
                else
                {
                    Log.v("Auto Respond", "No extras returned from contact.");
                }

                Uri result = data.getData();
                String id = result.getLastPathSegment();
                String[] projection = new String[]{ContactsContract.CommonDataKinds.Phone.NUMBER,ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME};
                cursor = getContentResolver().query(result, projection,
                        null, null, null);

                String contactName="";
                String contactNumber="";
                if(cursor != null && cursor.moveToFirst())
                {
                    String nameOfselectedContact=cursor.getString(cursor.getColumnIndex((ContactsContract.Contacts.DISPLAY_NAME)));
                    ArrayList<String> numbersOfSelectedContact=new ArrayList<String>();
                    Log.e("contact size", cursor.getCount()+"");
                    for(int i=0;i<cursor.getCount();i++)
                    {
                        numbersOfSelectedContact.add(cursor.getString(cursor.getColumnIndex((ContactsContract.CommonDataKinds.Phone.NUMBER))));
                        cursor.moveToNext();
                    }
                    cursor.close();

                }
                    break;
        }
    }

}

现在您将联系人姓名作为名为＆＃34; nameOfselectedContact＆＃34;的字符串。其所有数字都作为ArrayList命名为＆＃34; numbersOfSelectedContact＆＃34;然后，您可以根据需要使用它们（可以在对话框中显示它们）。

联系人选择器不返回任何结果

2 个答案: