我想从VB.NET中的.zip
文件中获取一个文件。我不需要提取所有.zip
文件,只需要一个文件。
我正在使用框架4.5。
答案 0 :(得分:2)
.NET Framework 4.5具有ZipFile
类,可以为您执行此操作。这段代码可以帮助您入门:
Dim zipPath As String = "Sample.zip"
Using archive = ZipFile.Open(zipPath, ZipArchiveMode.Read)
Dim entry = archive.GetEntry("MyFile.pdf")
Using reader As New BinaryReader(entry.Open())
System.IO.File.WriteAllBytes("MyFile.pdf", ReadAllBytes(reader))
End Using
End Using
ReadAllBytes()
是一个从二进制流中获取所有字节的辅助方法:
Public Shared Function ReadAllBytes(reader As BinaryReader) As Byte()
Const bufferSize As Integer = 4096
Using ms As New MemoryStream()
Dim buffer(bufferSize) As Byte
Dim count As Integer
Do
count = reader.Read(buffer, 0, buffer.Length)
If count > 0 Then ms.Write(buffer, 0, count)
Loop While count <> 0
Return ms.ToArray()
End Using
End Function
确保您使用的是.NET Framework 4.5或更高版本,并且已包含对System.IO.Compression
和System.IO.Compression.FileSystem
的引用。
答案 1 :(得分:0)
Using zip As ZipFile = ZipFile.Read(ExistingZipFile)
Dim e As ZipEntry = zip("DocumentToFind.txt")
e.Extract(OutputStream)
End Using
否则你可以这样使用ZipArchiveClass
Using zip As ZipArchive = ZipFile.Open(zipfile, ZipArchiveMode.Read)
Dim file = zip.Entries.Where(Function(x) x.Name = "fileToFind")
If file IsNot Nothing Then
file.ExtractToFile("yourFile")
End If
结束使用
答案 2 :(得分:0)
这将允许您逐行读取文本中的txt文件
Dim zipPath As String = "ZIP FILE LOCATION"
Using zipStream = New FileStream(last_pafx23_open, FileMode.Open)
Using archive = New ZipArchive(zipStream, ZipArchiveMode.Read)
For Each ent In archive.Entries
MsgBox(ent.ToString)
Using stream = ent.Open()
Using reader = New StreamReader(stream)
While Not reader.EndOfStream
MsgBox(reader.ReadLine)
End While
End Using
End Using
Next
End Using
End Using
答案 3 :(得分:-1)
使用ReadAllBytes()辅助函数跳过BinaryReader,改为使用ExtractToFile():
Imports System.IO.Compression
Using archive = ZipFile.Open("Sample.zip", ZipArchiveMode.Read)
Dim entry = archive.GetEntry("MyFile.pdf")
If entry IsNot Nothing then entry.ExtractToFile("MyFile.pdf")
End Using
当然还需要System.IO.Compression
和System.IO.Compression.FileSystem
的引用。