Question

我正在编写一个程序，需要从.txt文件中对引号进行排序并输出到另一个文件。我试图放入一个数组进行排序的QUOTES.txt文件有这样的引号

如果你达到了标记，你必须瞄准它的上方;每一个箭头     苍蝇感受到地球的吸引力。 Henry Wadsworth Longfellow

永远，绝不，永不放弃！温斯顿丘吉尔

伟大的作品不是靠力量而是靠坚持不懈。      塞缪尔约翰逊

由于缺乏目标而缺乏人才，更多的人失败了。比利星期天

孩子们从未擅长倾听长辈，但他们      从来没有模仿过他们。詹姆斯鲍德温

无需更改模板，有没有办法对完整的句子进行排序？现在它正在单独输入单词并对单词进行排序，但我希望句子保持不变，只能按句子的第一个字母排序。这是我写的代码：

#include <iostream>
#include <fstream>
#include <iomanip>
#include <string>
#include <cstdlib>
using namespace std;

template < typename T >
T sorting(T rays [], int size)
{
    int minIndx, i;
    T temp;

    for (int passCount = 0; passCount < size - 1; passCount++)
    {
        minIndx = passCount;

        for (int searchIndx = passCount + 1; searchIndx < size; searchIndx++)
            if (rays[searchIndx] < rays[minIndx])
                minIndx = searchIndx;

        temp = rays[minIndx];
        rays[minIndx] = rays[passCount];
        rays[passCount] = temp;
    }

    cout << endl << "Sorted:" << endl;
    for (i = 0; i < size; ++i)
    cout << rays[i] << endl;

    cout << endl;

    return (0);
}

int main()
{

    ifstream inNumbers("IntFile.txt");
    ifstream inFloaters("FloatFile.txt");
    ifstream inWords("QUOTES.txt");
    ofstream outNumbers("SortedInt.txt");
    ofstream outFloaters("SortedFloat.txt");
    ofstream outWords("SortedQuotes.txt");

    int i, length = 0, lengt = 0, leng = 0;
    int data[100];
    double data2[100];
    string data3[100];

    if (!inNumbers)
    {
        cerr << "IntFile.txt file could not be opened" << endl;
        exit(1);
    }

    if (!inFloaters)
    {
        cerr << "FloatFile.txt file could not be opened" << endl;
        exit(1);
    }

    if (!inWords)
    {
        cerr << "QUOTES.txt file could not be opened" << endl;
        exit(1);
    }

    for (i = 0; i < 100 && inNumbers; ++i)
    {
        inNumbers >> data[i];
        if (inNumbers)
        {
            length += 1;
        }
    }

    sorting(data, length);

    for (i = 0; i < 100 && inFloaters; ++i)
    {
        inFloaters >> data2[i];
        if (inFloaters)
        {
            lengt += 1;
        }
    }

    sorting(data2, lengt); 

    for (i = 0; i < 100 && inWords; ++i)
    {
        inWords >> data3[i];
        if (inWords)
        {
            leng += 1;
        }
    }

    sorting(data3, leng);
}

---------- EDIT ---------------

我将inWords的输入从inWords >> data3[i];更改为getline(inWords, data3[i];，所以现在它一次扫描一行。现在我只需要找出如何对这个新数组进行排序并保持引号不变。

Answer 1

很抱歉，我并没有将解决方案纳入您现有的代码，但这绝对有效：

#include <iostream>
#include <string>
#include <fstream>
#include <cassert>
#include <vector>
using namespace std;

int main() {
    ifstream iFile("QUOTES.txt");
    assert(iFile.is_open());

    vector<string> quoteLines, quotes;

    for (string s; getline(iFile, s);) quoteLines.push_back(s);

    iFile.close();

    /* deal with multi-line quotes by merging the stuff separated
     by empty lines into single strings */
    string tmpStr;
    for (const auto& s : quoteLines) {
        if (s == "") {
            /* if we come across an empty line, put the stuff we had so far into the vector
             and clear the temporary string */
            quotes.push_back(tmpStr);
            tmpStr.clear();
        } else {
            /* if there's already stuff in the temporary string, then append a space to it. */
            /* then, append the current line */
            tmpStr += ((tmpStr.size() == 0)?"":" ") + s;
        }
    }

    /* sort the quotes */
    sort(quotes.begin(), quotes.end());

    for (const auto& s : quotes) cout << s << endl << endl;

    return 0;
}

将.txt文件中的完整句子输入到数组中

1 个答案: