Question

我试图改变我的代码，所以当没有匹配的行时，＆＃34; ean13＆＃34;在webshop_stock中它必须INSERT。

但是mysql不接受我测试的代码，我尝试了一些东西以使其工作。我在Google上的搜索没有找到一个有效的例子＆＃34; INSERT INTO - JOIN - ON DUPLICATE KEY UPDATE＆＃34;这可能吗？

此时的问题是我的行在不存在时会被创建，但存在的行不会更新。

测试了以下代码：

    $get_input = "
INSERT INTO webshop_stock 
   (id_warehouse,id_product,id_product_attribute,ean13, physical_quantity, usable_quantity)
   SELECT
        '1',
        pa.id_product,
        pa.id_product_attribute,
        pa.ean13, 
        ai.quantity,
        ai.quantity
    FROM
        webshop_product_attribute pa, 
        Adcount_input ai 
    WHERE 
        pa.ean13 = ai.ean13 
    AND NOT EXISTS 
        (SELECT id_product_attribute FROM webshop_stock WHERE id_product_attribute = pa.id_product_attribute)
    ON DUPLICATE KEY UPDATE 
        physical_quantity = ai.quantity,
        usable_quantity = ai.quantity
";

原始代码：

$get_input = "
UPDATE
    webshop_stock AS s
JOIN(
    SELECT 
        pa.ean13, 
        pa.id_product_attribute,
        pa.id_product,
        ai.quantity 
    FROM 
        webshop_product_attribute pa, 
        Adcount_input ai 
    WHERE 
        pa.ean13=ai.ean13) q
SET
        s.id_warehouse = 1,
        s.id_product = q.id_product,
        s.id_product_attribute = q.id_product_attribute,
        s.ean13 = q.ean13,
        s.physical_quantity = q.quantity,
        s.usable_quantity = q.quantity 
WHERE 
        s.id_product_attribute = q.id_product_attribute";

Answer 1

已解决此代码可以满足我的需求。

    $get_input = "
INSERT INTO webshop_stock 
   (id_warehouse,id_product,id_product_attribute,ean13, physical_quantity, usable_quantity)
   SELECT
        '1',
        pa.id_product,
        pa.id_product_attribute,
        pa.ean13, 
        ai.quantity,
        ai.quantity
    FROM
        webshop_product_attribute pa, 
        Adcount_input ai 
    WHERE 
        pa.ean13 = ai.ean13
    ON DUPLICATE KEY UPDATE
        physical_quantity = ai.quantity, usable_quantity = ai.quantity

";

Answer 2

语法为：

INSERT <table> <field list>
SELECT ... JOIN ...

mysql中有 NO INSERT JOIN SELECT。它是INSERT SELECT JOIN。

http://dev.mysql.com/doc/refman/5.1/en/insert-select.html

是否可以使用＆＃39; join＆＃39;在INSERT ON DUPLICATE KEY UPDATE

2 个答案: