Question

如何在按钮_click（）

中的asp.net（vb）中单击另一个按钮后显示链接按钮

它将错误称为“对象引用未设置为对象的实例。”

我在我的代码中完成了这个

受保护的Sub InsertButton_Click（ByVal sender As Object，ByVal e As System.EventArgs）

    Dim receipt As LinkButton = FormView1.FindControl("LinkButton1")

   ' receipt.Enabled = "true"
   ' receipt.EnableTheming = "true"
   ' receipt.EnableViewState = "true"
    receipt.Visible = "true"

End Sub

Answer 1

删除表单名称，如下所示：

Dim receipt As LinkButton = FindControl("LinkButton1")
If (Not receipt Is Nothing)
   ' receipt.Enabled = "true"
   ' receipt.EnableTheming = "true"
   ' receipt.EnableViewState = "true"
    receipt.Visible = "true"
End if

Answer 2

或者像这样...

    LinkButton1.Visible = "true"

如何在button_click（）中的asp.net（vb）中单击另一个按钮后显示链接按钮

2 个答案: