写入变量整数时ByteBuffer.js出现意外结果

Question

下面，我试图将0x16写为变量整数。我期待看到0x2C，但我得到0x16。知道如何调整我对ByteBuffer的使用以获得预期的结果吗？请按照以下评论：

http://jsfiddle.net/jslim180/h1ojuc54/

ByteBuffer = window.dcodeIO.ByteBuffer

b = new ByteBuffer(DEFAULT_CAPACITY=4, ByteBuffer.LITTLE_ENDIAN)

console.log '22 decimal is 0x16 hex: ' + (22).toString(16)

# 22 can be represented in less than 7 bits so the least significant bit 
# should be 0 (indicating that no additional bytes are needed)
b.writeVarint32 22 
b.printDebug() # Not expected: prints 0x16 .. this did not bitshift at all

# If I bit-shift manually, I get the expected result: 0x2C
console.log (0x16<<1).toString(16) # prints 2c

https://github.com/dcodeIO/ByteBuffer.js/wiki/API

（顺便说一句：这是coffeescript，没有括号的javascript）

Answer 1

ByteBuffer正在写出无符号的varint。我需要使用writeVaruint32。 https://github.com/dcodeIO/ByteBuffer.js/issues/44