我试图将UDisks2与Qt应用程序连接,并且读取自定义属性会使程序崩溃。
对于SMART属性,一切正常(包括custom properties),但当我尝试读取RAID设备属性ActiveDevices时,我收到Qt致命错误并且应用程序崩溃
以下是一个测试程序,用于说明行为:
#include <QApplication>
#include <QDBusMetaType>
#include <QDBusConnection>
#include <QDBusInterface>
#include <QDebug>
//create the structure as defined in
// http://udisks.freedesktop.org/docs/latest/gdbus-org.freedesktop.UDisks2.MDRaid.html#gdbus-property-org-freedesktop-UDisks2-MDRaid.ActiveDevices
struct MDRaidMember {
QDBusObjectPath block;
qint32 slot;
QStringList state;
qint64 numReadErrors;
QVariantMap expansion;
};
Q_DECLARE_METATYPE(MDRaidMember)
//marshalling operator
QDBusArgument &operator<<(QDBusArgument &argument, const MDRaidMember& raidMember)
{
argument.beginStructure();
argument << raidMember.block;
argument << raidMember.slot;
argument << raidMember.state;
argument << raidMember.numReadErrors;
argument << raidMember.expansion;
argument.endStructure();
return argument;
}
//unmarshall operator
const QDBusArgument &operator>>(const QDBusArgument &argument, MDRaidMember& raidMember)
{
argument.beginStructure();
argument >> raidMember.block;
argument >> raidMember.slot;
argument >> raidMember.state;
argument >> raidMember.numReadErrors;
argument >> raidMember.expansion;
argument.endStructure();
return argument;
}
int main(int argc, char *argv[]) {
QApplication app(argc, argv);
//register the type, everything looks fine
qDebug() << qRegisterMetaType<MDRaidMember>("MDRaidMember");
qDebug() << qDBusRegisterMetaType<MDRaidMember>();
QDBusInterface iface("org.freedesktop.UDisks2",
"/org/freedesktop/UDisks2/mdraid/9aec6784_86ec37d4_8c1c6add_4dc9fe81",
"org.freedesktop.UDisks2.MDRaid",
QDBusConnection::systemBus());
//read some properties
qDebug() << iface.property("UUID");
qDebug() << iface.property("ActiveDevices"); //crash the test program!
return app.exec();
}
执行此代码会产生以下输出
1057
1057
QVariant(QString, "9aec6784:86ec37d4:8c1c6add:4dc9fe81")
Cannot construct placeholder type QDBusRawType
zsh: abort (core dumped) ./app/test_members
有人遇到过这种情况吗?我根本不认为它与我的代码有关,因为如果没有声明自定义类型(仅保留 main 函数的内容),结果是相同的。
答案 0 :(得分:2)
我没有为此找到正确答案,但这是一种解决方法:在接口Get
上调用org.freedesktop.DBus.Properties
方法并手动解组结果。棘手的部分是确定结果的内容(它是 QVariant 包含 QDBusVariant 包含 QDBusArgument )
更新的main
功能:
//...
int main(int argc, char *argv[]) {
QApplication app(argc, argv);
//register the type, everything looks fine
qDebug() << qRegisterMetaType<MDRaidMember>("MDRaidMember");
qDebug() << qDBusRegisterMetaType<MDRaidMember>();
QDBusInterface iface("org.freedesktop.UDisks2",
"/org/freedesktop/UDisks2/mdraid/9aec6784_86ec37d4_8c1c6add_4dc9fe81",
"org.freedesktop.DBus.Properties",
QDBusConnection::systemBus());
QDBusMessage reply = iface.call("Get", "org.freedesktop.UDisks2.MDRaid", "ActiveDevices");
QVariant v = reply.arguments().first();
QDBusArgument arg = v.value<QDBusVariant>().variant().value<QDBusArgument>();
QList<MDRaidMember> members;
arg.beginArray();
while(!arg.atEnd()) {
MDRaidMember m;
arg >> m;
members << m;
}
qDebug() << members;
return app.exec();
}