您好我想将我的jsonRootName修改为问候语,如下所述。请在下面找到我的代码。
我正在举办一个Greeting课程
package hello;
import java.util.HashMap;
import java.util.Map;
import org.springframework.hateoas.ResourceSupport;
import com.fasterxml.jackson.annotation.JsonCreator;
import com.fasterxml.jackson.annotation.JsonIgnoreProperties;
import com.fasterxml.jackson.annotation.JsonInclude;
import com.fasterxml.jackson.annotation.JsonInclude.Include;
import com.fasterxml.jackson.annotation.JsonProperty;
import com.fasterxml.jackson.annotation.JsonRootName;
import com.fasterxml.jackson.databind.ObjectMapper;
@JsonIgnoreProperties(ignoreUnknown = true)
@JsonRootName(value = "Greeting")
public class Greeting {
private String fname;
private String lname;
public String getFname() {
return fname;
}
public void setFname(String fname) {
this.fname = fname;
}
public String getLname() {
return lname;
}
public void setLname(String lname) {
this.lname = lname;
}
}
和我的RestController类如下。
package hello;
import static org.springframework.hateoas.mvc.ControllerLinkBuilder.linkTo;
import static org.springframework.hateoas.mvc.ControllerLinkBuilder.methodOn;
import java.util.ArrayList;
import java.util.List;
import org.springframework.hateoas.Link;
import org.springframework.hateoas.Resource;
import org.springframework.hateoas.Resources;
import org.springframework.http.HttpEntity;
import org.springframework.http.HttpStatus;
import org.springframework.http.ResponseEntity;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.ResponseBody;
@Controller
@RequestMapping("/greeting")
public class GreetingController {
@RequestMapping(method = RequestMethod.GET, produces = "application/json")
@ResponseBody
public ResponseEntity<Resources<Resource>> greeting() {
Greeting greeting = new Greeting();
greeting.setFname("nik");
greeting.setLname("hil");
Link link = linkTo(GreetingController.class).slash(greeting.getFname()).withSelfRel();
Resource<Greeting> res = new Resource<>(greeting , link.expand(greeting.getFname()));
Greeting greeting1 = new Greeting();
greeting1.setFname("nik");
greeting1.setLname("hil");
Link link1 = linkTo(GreetingController.class).slash(greeting.getFname()).withSelfRel();
Resource<Greeting> res1 = new Resource<>(greeting , link1.expand(greeting.getFname()));
List<Resource> listRes = new ArrayList<>();
listRes.add(res);
listRes.add(res1);
Resources<Resource> resourceList = new Resources<>(listRes);
return new ResponseEntity<Resources<Resource>>(resourceList,
HttpStatus.OK);
}
}
和
我正在获得如下的JSON Fromat。
{
"_embedded":
{
"greetingList":
[
{
"fname": "nik",
"lname": "hil",
"_links":
{
"self":
{
"href": "http://localhost:8080/greeting/nik"
}
}
},
{
"fname": "nik",
"lname": "hil",
"_links":
{
"self":
{
"href": "http://localhost:8080/greeting/nik"
}
}
}
]
}
}
我希望如下所示
{
"_embedded":
{
"Greeting":
[
{
"fname": "nik",
"lname": "hil",
"_links":
{
"self":
{
"href": "http://localhost:8080/greeting/nik"
}
}
},
{
"fname": "nik",
"lname": "hil",
"_links":
{
"self":
{
"href": "http://localhost:8080/greeting/nik"
}
}
}
]
}
}
我希望JSON Root名称显示为“Greeting”而不是“GreetingList”。请建议。
答案 0 :(得分:0)
这篇文章解决了你的问题:@JsonRootName not work as I want
你需要使用mapper.configure(SerializationFeature.UNWRAP_ROOT_VALUE,true);不是WRAP_ROOT_VALUE。