Question

我有一个数组，一个像这样的json对象

["www.flipkart.com","www.amazon.in"]
[
    {
        "product_name": "Deepcool",
        "dollar_price": 2.9697123914957047,
        "product_code": "C60_4123"
    },
    {
        "product_name": "Deepcool XFAN",
        "dollar_price": 5.473902300000191,
        "product_code": "C60_4123"
    },
    {
        "product_name": "DeepcoolXFAN80",
        "dollar_price": 5.473902300000191,
        "product_code": "C60_4123"
    }
]

我只是将此对象设置为隐藏变量，如下所示

<input value="[object Object],[object Object],[object Object]" class="graphobj1" type="hidden">
<input value="www.flipkart.com","www.amazon.in" class="graphobj2" type="hidden">

当我从页面中回溯这个json对象时，就像这样

var z1 = $('.graphobj1');
var z2 = $('.graphobj2');

当我提醒它时，它显示错误TypeError: cyclic object value，我怎样才能让我的对象返回原样？

Answer 1

使用 JSON.stringify() 和 JSON.parse()

var a = ["www.flipkart.com", "www.amazon.in"],
  b = [{
    "product_name": "Deepcool",
    "dollar_price": 2.9697123914957047,
    "product_code": "C60_4123"
  }, {
    "product_name": "Deepcool XFAN",
    "dollar_price": 5.473902300000191,
    "product_code": "C60_4123"
  }, {
    "product_name": "DeepcoolXFAN80",
    "dollar_price": 5.473902300000191,
    "product_code": "C60_4123"
  }],
  $input1 = $('input.graphobj1'),
  $input2 = $('input.graphobj2');

$input1.val(JSON.stringify(a));
$input2.val(JSON.stringify(b));

console.log(JSON.parse($input1.val()));
console.log(JSON.parse($input2.val()));

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<input class="graphobj1" type="hidden">
<input class="graphobj2" type="hidden">

TypeError：解析隐藏值时javascript中的循环对象值

1 个答案: