XML属性中的SUDS和命名空间

时间:2015-02-05 00:57:10

标签: python soap suds

我在使用NetSuite SOAP API很好地使用SUDS时遇到了一些麻烦。我已经玩过SoapUI来发送NetSuite XML,它可以用于我想要的调用,但是我无法使用Python。这是有效的XML:

<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" 
xmlns:urn="urn:messages_2015_1.platform.webservices.netsuite.com" 
xmlns:urn1="urn:core_2015_1.platform.webservices.netsuite.com"
xmlns:xsd="http://www.w3.org/2001/XMLSchema"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
>
   <soapenv:Header>
      <urn:preferences>
      </urn:preferences>
      <urn:partnerInfo>
      </urn:partnerInfo>
      <urn:applicationInfo>

      </urn:applicationInfo>
      <urn:passport>
         <urn1:email>*****</urn1:email>
         <urn1:password>*****</urn1:password>
         <urn1:account>*****</urn1:account>
         <!--Optional:-->
         <urn1:role internalId=*****>
         </urn1:role>
      </urn:passport>
   </soapenv:Header>
   <soapenv:Body>
      <urn:get>
        <urn1:baseRef internalId="2026" type="customer" xsi:type="urn1:RecordRef"/>
      </urn:get>
   </soapenv:Body>
</soapenv:Envelope>

在Python中,我已经生成了一个RecordRef对象并填充了它,但它并不关心我的输入:

>>> recordRef = client.factory.create('ns4:RecordRef')
>>> recordRef
(RecordRef){
   name = None
   _internalId = ""
   _externalId = ""
   _type = ""
 }
>>> recordRef._internalId = 2026
>>> recordRef._type = 'customer'
>>> recordRef
(RecordRef){
   name = None
   _internalId = 2026
   _externalId = ""
   _type = "customer"
 }
>>> client.service.get(recordRef)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/local/lib/python2.7/dist-packages/suds/client.py", line 521, in __call__
    return client.invoke(args, kwargs)
  File "/usr/local/lib/python2.7/dist-packages/suds/client.py", line 581, in invoke
    result = self.send(soapenv)
  File "/usr/local/lib/python2.7/dist-packages/suds/client.py", line 619, in send
    description=tostr(e), original_soapenv=original_soapenv)
  File "/usr/local/lib/python2.7/dist-packages/suds/client.py", line 670, in process_reply
    raise WebFault(fault, replyroot)
suds.WebFault: Server raised fault: 'org.xml.sax.SAXException: Invalid type: customer'
>>> 

当我查看发送出去的XML时,我注意到xsi:type正在设置,但类型不是。

如果我将客户(真的是xsi:customer)设置为在SoapUI中使用的相同值,我会收到有关未设置客户的错误:

(ReadResponse){
   status = 
      (Status){
         _isSuccess = False
         statusDetail[] = 
            (StatusDetail){
               _type = "ERROR"
               code = "RCRD_TYPE_REQD"
               message = "The record type is required."
            },
      }
 }
>>> recordRef
(RecordRef){
   name = None
   _internalId = 2026
   _externalId = ""
   _type = "ns1:RecordRef"
 }

我在大约五年内没有使用SOAP做过任何事情,而且之前从未在Python中做过任何事情。任何建议将不胜感激。

1 个答案:

答案 0 :(得分:0)

想出来,我需要编写一个调用marshalled()方法的插件:

class FixXML(suds.plugin.MessagePlugin):
        def __init__(self):
                pass

        def marshalled(self, context):
                #the attribute type is really xsi:type, which we need to set but is being handled wrong
                #get the Netsuite data type
                wsdlDataType = context.envelope.getChild('Body').getChild('get').getChild('baseRef').getAttribute('type').getValue()
                #now rewrite xsi:type so its something namespacey
                context.envelope.getChild('Body').getChild('get').getChild('baseRef').getAttribute('type').setValue('ns0:RecordRef')
                #next we need to add a type attribute without a namespace that contains the data type from the wsdl
                typeAttr = suds.sax.attribute.Attribute('type')
                typeAttr.setValue(wsdlDataType)
                context.envelope.getChild('Body').getChild('get').getChild('baseRef').append(typeAttr)