我建立了一个练习网络应用程序,我正在使用这样的两个表:
表1:weekly_stats
| id | code | type | date | time |
|----|--------------|--------------------|------------|----------|
| 1 | CC | 1 | 2015-02-04 | 19:15:00 |
| 2 | CC | 2 | 2015-01-28 | 19:15:00 |
| 3 | CPC | 1 | 2015-01-26 | 19:15:00 |
| 4 | CPC | 1 | 2015-01-25 | 19:15:00 |
| 5 | CP | 1 | 2015-01-24 | 19:15:00 |
| 6 | CC | 1 | 2015-01-23 | 19:15:00 |
| .. | ... | ... | ... | ... |
表2:global_stats
| id | exercise_number |correct | wrong |
|----|-----------------|--------|-----------|
| 1 | 138 | 1 | 0 |
| 2 | 246 | 1 | 0 |
| 3 | 988 | 1 | 10 |
| 4 | 13 | 5 | 0 |
| 5 | 5 | 4 | 7 |
| 6 | 5 | 4 | 7 |
| .. | ... | ... | ... |
我想要的是获得MAX(正确错误)和MIN(正确错误),现在我正在使用此查询:
SELECT
exercise_number,
date,
time
FROM weekly_stats AS w JOIN global_stats AS g
ON w.id=g.id
WHERE correct - wrong = (SELECT MAX(correct - wrong) from global_stats)
UNION
SELECT
exercise_number,
date,
time
FROM weekly_stats AS w JOIN global_stats AS g
ON w.id=g.id
WHERE correct - wrong = (SELECT MIN(correct - wrong) from global_stats);
此查询工作正常,除了一件事:当" WHERE正确 - 错误=(SELECT MIN(正确 - 错误)[...]"选择多行,选择的行是第一行,但我想返回最新的(换句话说:按日期时间(日期,时间)排序)。是否可能?
谢谢!
答案 0 :(得分:1)
我认为你可以这样解决:
SELECT * FROM (
SELECT
1 as sort_column,
exercise_number,
date,
time
FROM weekly_stats AS w JOIN global_stats AS g
ON w.id=g.id
WHERE correct - wrong = (SELECT MAX(correct - wrong) from global_stats)
ORDER BY date DESC, time DESC
LIMIT 1 ) as a
UNION
SELECT * FROM (
SELECT
2 as sort_column,
exercise_number,
date,
time
FROM weekly_stats AS w JOIN global_stats AS g
ON w.id=g.id
WHERE correct - wrong = (SELECT MIN(correct - wrong) from global_stats)
ORDER BY date DESC, time DESC
LIMIT 1) as b
ORDER BY sort_column;
以下是关于UNION如何运作的documentation。