Question

我在使用我正在迭代的函数中创建的列表时遇到问题。我的代码目前看起来像这样：

def get_things(i):
    html=str(site[i])
    browser = webdriver.Chrome()  # Optional argument, if not specified will search path.
    browser.get(html);
    playerlist=[]
    teamlist=[]
    all_players = browser.find_elements_by_xpath("//a[@class='name']")
    all_teams = browser.find_elements_by_xpath("//td[@class='last']")
    for a in all_players:
        playerlist.append(str(a.text))
    print playerlist
    for td in all_teams:
        teamlist.append(str(td.text))
    print teamlist
    browser.quit()
    return playerlist, teamlist

然后我想在我的程序中稍后在另一个函数中使用teamlist和playerlist。

for i in xrange(0,2):
    get_things(i)
    print teamlist    #This is where Im told teamlist doesn't exist
    print playerlist   #This is where I'm told playerlist doesn't exist
    print_sheet(teamlist, playerlist)

这两个打印报表对我来说是确保程序正在拾取项目。不过，我的问题是我被告知团队列表和玩家列表不存在。

NameError: name 'teamlist' is not defined

我相信return语句应该使这些可用于程序的其余部分，但事实并非如此。

如何将这些列表提供给程序的其余部分？

Answer 1

使用以下

(teamlist, playerlist)=get_things(I)

当你的功能返回时，你需要处理它。

实施例

def add(a,b):
    return a+b
n=add(6,8)
print n #n is 14

Answer 2

您需要将返回值分配给get_things到某些变量

for i in xrange(0,2):
    playerlist , teamlist = get_things(i) # missing this
    print teamlist    #This is where Im told teamlist doesn't exist
    print playerlist   #This is where I'm told playerlist doesn't exist
    print_sheet(teamlist, playerlist)

使用在该函数之外的函数中创建的列表python

2 个答案: