Question

有很多关于格式化JSON的帖子，但我找不到适合我奇怪情况的帖子......这是我的数据源：

data = [{ "LoanOfficer": "Brett", "Year": 2014, "Month": 10, "FundedVolume": 304032.0000, "FundedUnits": 2.0000, "NewAppUnits": 2.0000, "RateLockUnits": 1.0000 },
    { "LoanOfficer": "Brett", "Year": 2014, "Month": 11, "FundedVolume": 179450.0000, "FundedUnits": 1.0000, "NewAppUnits": 1.0000, "RateLockUnits": 3.0000 },
    { "LoanOfficer": "Carlos", "Year": 2014, "Month": 10, "FundedVolume": 576615.0000, "FundedUnits": 3.0000, "NewAppUnits": 5.0000, "RateLockUnits": 3.0000 },
    { "LoanOfficer": "Carlos", "Year": 2014, "Month": 11, "FundedVolume": 341303.0000, "FundedUnits": 2.0000, "NewAppUnits": 5.0000, "RateLockUnits": null },
    { "LoanOfficer": "Carlos", "Year": 2014, "Month": 12, "FundedVolume": null, "FundedUnits": null, "NewAppUnits": null, "RateLockUnits": 1.0000 },
    { "LoanOfficer": "Elaine", "Year": 2014, "Month": 10, "FundedVolume": null, "FundedUnits": null, "NewAppUnits": 1.0000, "RateLockUnits": 1.0000 },
    { "LoanOfficer": "Elaine", "Year": 2014, "Month": 11, "FundedVolume": 348500.0000, "FundedUnits": 2.0000, "NewAppUnits": 1.0000, "RateLockUnits": 1.0000 },
    { "LoanOfficer": "Eric", "Year": 2014, "Month": 10, "FundedVolume": 768464.0000, "FundedUnits": 6.0000, "NewAppUnits": 5.0000, "RateLockUnits": 7.0000 }];

因此，您可以看到我有相同LoanOfficer的多个条目。理想情况下，我想重新格式化并总结，以便每LoanOfficer只有一个条目并添加FundedVolume＆amp; *Units对此：

data = [{ "LoanOfficer": "Brett", "FundedVolume": 483482.0000, "FundedUnits": 3.0000, "NewAppUnits": 3.0000, "RateLockUnits": 4.0000 },
    { "LoanOfficer": "Carlos", "FundedVolume": 917918.0000, "FundedUnits": 5.0000, "NewAppUnits": 10.0000, "RateLockUnits": 4.0000 },
    { "LoanOfficer": "Elaine", "FundedVolume": 348500.0000, "FundedUnits": 2.0000, "NewAppUnits": 2.0000, "RateLockUnits": 2.0000 },
    { "LoanOfficer": "Eric", "FundedVolume": 768464.0000, "FundedUnits": 6.0000, "NewAppUnits": 5.0000, "RateLockUnits": 7.0000 }];

我试过这个作为起点，但我很确定这不是正确的路线。

var UniqueD = {};
$.each(data, function () {
    i = 0;
    if (UniqueD[this.LoanOfficer])
        i = UniqueD[this.LoanOfficer];
    UniqueD[this.LoanOfficer] = i + this.NewAppUnits;
});

编辑：我有一个工作功能，可以提供我想要的东西：

var rawdata = [...] // data source
var listOfOfficerStats = []; // new data
function Combine() {
    for (i = 0; i < rawData.length; i++)
    {
        var loExist = -1;
        for (j = 0; j < listOfOfficerStats.length; j++)
        {
            if (listOfOfficerStats[j].LoanOfficer == rawData[i].LoanOfficer)
                loExist = j;
        }

        if (loExist == -1)
        {
            //New
            var newObject = new Object();
            newObject.LoanOfficer = rawData[i].LoanOfficer;
            newObject.FundedVolume = rawData[i].FundedVolume;
            newObject.FundedUnits = rawData[i].FundedUnits;
            newObject.NewAppVolume = rawData[i].NewAppVolume;
            newObject.NewAppUnits = rawData[i].NewAppUnits;
            newObject.RateLockVolume = rawData[i].RateLockVolume;
            newObject.RateLockUnits = rawData[i].RateLockUnits;
            listOfOfficerStats.push(newObject);
        }
        else
        {
            //Add To Existing
            listOfOfficerStats[loExist].FundedVolume += rawData[i].FundedVolume;
            listOfOfficerStats[loExist].FundedUnits += rawData[i].FundedUnits;
            listOfOfficerStats[loExist].NewAppVolume += rawData[i].NewAppVolume;
            listOfOfficerStats[loExist].NewAppUnits += rawData[i].NewAppUnits;
            listOfOfficerStats[loExist].RateLockVolume += rawData[i].RateLockVolume;
            listOfOfficerStats[loExist].RateLockUnits += rawData[i].RateLockUnits;
        }
    }
}

Answer 1

这是一个通用函数：

function sum(data, key, fields) {
    return data.reduce(function(out, rec) {
        var k = rec[key];
        out[k] = out[k] || {};
        fields.forEach(function(f) {
            out[k][f] = (out[k][f] || 0) + (rec[f] || 0);
        });
        return out;
    }, {})
}


// test


data = [{ "LoanOfficer": "Brett", "Year": 2014, "Month": 10, "FundedVolume": 304032.0000, "FundedUnits": 2.0000, "NewAppUnits": 2.0000, "RateLockUnits": 1.0000 },
    { "LoanOfficer": "Brett", "Year": 2014, "Month": 11, "FundedVolume": 179450.0000, "FundedUnits": 1.0000, "NewAppUnits": 1.0000, "RateLockUnits": 3.0000 },
    { "LoanOfficer": "Carlos", "Year": 2014, "Month": 10, "FundedVolume": 576615.0000, "FundedUnits": 3.0000, "NewAppUnits": 5.0000, "RateLockUnits": 3.0000 },
    { "LoanOfficer": "Carlos", "Year": 2014, "Month": 11, "FundedVolume": 341303.0000, "FundedUnits": 2.0000, "NewAppUnits": 5.0000, "RateLockUnits": null },
    { "LoanOfficer": "Carlos", "Year": 2014, "Month": 12, "FundedVolume": null, "FundedUnits": null, "NewAppUnits": null, "RateLockUnits": 1.0000 },
    { "LoanOfficer": "Elaine", "Year": 2014, "Month": 10, "FundedVolume": null, "FundedUnits": null, "NewAppUnits": 1.0000, "RateLockUnits": 1.0000 },
    { "LoanOfficer": "Elaine", "Year": 2014, "Month": 11, "FundedVolume": 348500.0000, "FundedUnits": 2.0000, "NewAppUnits": 1.0000, "RateLockUnits": 1.0000 },
    { "LoanOfficer": "Eric", "Year": 2014, "Month": 10, "FundedVolume": 768464.0000, "FundedUnits": 6.0000, "NewAppUnits": 5.0000, "RateLockUnits": 7.0000 }];

res = sum(data, "LoanOfficer", ["FundedVolume", "FundedUnits"]);
document.write(JSON.stringify(res));

Answer 2

Here's a version使用lodash和一系列groupBy，map和reduce：

var data = [...]; //assuming your original data array here

function sum(total, n) {
    return total + n;
}

function sumProperty(data, prop) {
    return _.reduce(_.pluck(data, prop), sum);
}

var groups = _.groupBy(data, 'LoanOfficer');
var reduced = _.map(groups, function(group, groupName) {
    return {
        LoanOfficer: groupName,
        FundedVolume: sumProperty(group, 'FundedVolume'),
        NewAppUnits: sumProperty(group, 'NewAppUnits'),
        RateLockUnits: sumProperty(group, 'RateLockUnits')
    };
});

这绝不是最佳选择。使用一些更专业的代码，你可以通过仅data循环一次来进行分组和同时构建所有总和来改善这一点。

重构和压缩JSON对象

2 个答案: