Question

我正在尝试用Java编写一个可以处理POST请求的简单HTTP服务器。当我的服务器成功收到GET时，它会在POST上崩溃。

这是服务器

public class RequestHandler {
    public static void main(String[] args) throws Exception {
        HttpServer server = HttpServer.create(new InetSocketAddress(8080), 0);
        server.createContext("/requests", new MyHandler());
        server.setExecutor(null); // creates a default executor
        server.start();
    }

    static class MyHandler implements HttpHandler {
        public void handle(HttpExchange t) throws IOException {
            String response = "hello world";
            t.sendResponseHeaders(200, response.length());
            System.out.println(response);
            OutputStream os = t.getResponseBody();
            os.write(response.getBytes());
            os.close();
        }
    }
}

这是我用来发送POST的Java代码

// HTTP POST request
private void sendPost() throws Exception {

    String url = "http://localhost:8080/requests";
    URL obj = new URL(url);
    HttpsURLConnection con = (HttpsURLConnection) obj.openConnection();

    //add reuqest header
    con.setRequestMethod("POST");
    con.setRequestProperty("User-Agent", USER_AGENT);
    con.setRequestProperty("Accept-Language", "en-US,en;q=0.5");

    String urlParameters = "sn=C02G8416DRJM&cn=&locale=&caller=&num=12345";

    // Send post request
    con.setDoOutput(true);
    DataOutputStream wr = new DataOutputStream(con.getOutputStream());
    wr.writeBytes(urlParameters);
    wr.flush();
    wr.close();

    int responseCode = con.getResponseCode();
    System.out.println("\nSending 'POST' request to URL : " + url);
    System.out.println("Post parameters : " + urlParameters);
    System.out.println("Response Code : " + responseCode);

    BufferedReader in = new BufferedReader(
            new InputStreamReader(con.getInputStream()));
    String inputLine;
    StringBuffer response = new StringBuffer();

    while ((inputLine = in.readLine()) != null) {
        response.append(inputLine);
    }
    in.close();

    //print result
    System.out.println(response.toString());
}

每次POST请求在此行崩溃

HttpsURLConnection con = (HttpsURLConnection) obj.openConnection();

但是当我将URL更改为我发现它的示例中提供的URL时，它可以正常工作。

Answer 1

而不是

HttpsURLConnection con = (HttpsURLConnection) obj.openConnection();

使用

HttpURLConnection con = (HttpURLConnection) obj.openConnection();

您正在连接到非HTTPS的网址。当您调用obj.openConnection()时，它会决定连接是HTTP还是HTTPS，并返回相应的对象。当它http时，它不会返回HttpsURLConnection，因此您无法转换为它。

但是，由于HttpsURLconnection扩展了HttpURLConnection，因此使用HttpURLConnection将适用于http和https个网址。您在代码中调用的方法都存在于HttpURLConnection类中。

Java httpserver在收到POST请求时崩溃

1 个答案: