Question

我需要这个嵌套循环才能工作并且简单

def triangle():
      print("Making a Triangle")
      base = 6
      while base > 0:
            print('0',0,base)
            base = base - 1
 triangle()

我目前的输出是：

Making a Triangle
0 0 6
0 0 5
0 0 4
0 0 3
0 0 2
0 0 1

我需要输出看起来像这样：

Answer 1

您可以使用乘法*运算符通过重复一个字符来创建字符串。此外，这将是for循环的非常直接的应用程序。

def triangle(n):
    print('making a triangle')
    for zeroes in range(n):
        print('0' * (n-zeroes))

测试

>>> triangle(6)
making a triangle
000000
00000
0000
000
00
0

虽然如果你想坚持while循环，你可以做

def triangle(n):
    print('Making a triangle')
    while n > 0:
        print('0' * n)
        n -= 1

Answer 2

Cyber的回答很好，以下是一些内容：

>>> for i in ['0'*j for j in range(n,0,-1)]: print (i) # Old-Style
... 
000000
00000
0000
000
00
0

>>> print('\n'.join(['0'*i for i in range(n, 0, -1)])) # Thanks to Hannes Ovren
000000
00000
0000
000
00
0

>>> print('\n'.join('0'*i for i in range(n, 0, -1)))    # Using a generator expression
000000
00000
0000
000
00
0

>>> print '\n'.join([('0'*6)[:n-i] for i in range(n)])  # Little complicated
000000
00000
0000
000
00
0

嵌套循环三角形与python

2 个答案: