Question

我在使用Pipe.send在此代码中工作时遇到了一些问题。我最不想做的是在fork中运行时向外部进程发送和接收消息。这最终将被集成到一个pexpect循环中，用于与解释器进程交谈。

from multiprocessing import Process, Pipe
from pexpect import spawn


class CockProc(Process):

    def start(self):
        self.process = spawn('coqtop', ['-emacs-U'])

    def run(self, conn):
        while True:
            if not conn.poll():
                cmd = conn.recv()
                self.process.send(cmd)
            self.process.expect('\<\/prompt\>')
            result = self.process.before + self.process.after + " "
            conn.send(result)


q, p = Pipe()

proc = CockProc()
proc.start()
proc.run(p)
res = q.recv()
command = raw_input(res + " ")

q.send(command)
res = q.recv()
parent_conn.send('OHHAI')
p.join()
    `

Answer 1

这样可行，但可能需要更多工作。不确定我可以创建和循环多少这些。

from multiprocessing import Process, Pipe
from pexpect import spawn


class CockProc(Process):

    def start(self):
        self.process = spawn('coqtop', ['-emacs-U'])

    def run(self, conn):
        if conn.poll():
            cmd = conn.recv()
            self.process.send(cmd + "\n")
            print "sent comm"
        self.process.expect('\<\/prompt\>')
        result = self.process.before + self.process.after + " "
        conn.send(result)

here, there = Pipe(duplex=True)

proc = CockProc()
proc.start()
proc.run(there)

while True:
    if here.poll():
        res = here.recv()
        command = raw_input(res + " ")
        here.send(command)
    proc.run(there)

在Python中使用multiprocessing.Pipe（）发送和接收异步

1 个答案: