Question

以下是我希望从我的脚本中获得的一些示例结果：示例1：客户12仅提供服务＆＃39; NEI2＆＃39;。那么结果应该是

AcctNum  PStatus  IStatus
12       1        5

示例2：如果客户21具有服务＆＃39; PN20＆＃39;，＆＃39; PN4＆＃39;和＆＃39; FL1＆＃39;那么结果应该是

AcctNum  PStatus  IStatus
    21       3        2
    21       4        5

回复永远是＆＃39; Y＆＃39;。如果需要，您可以修改脚本。谢谢。

以下是剧本：

    SELECT distinct  A.AcctNum,
      CASE 
        WHEN O.Order = 'NEI2' THEN '1'
        WHEN AV.Query IN ('PNE1','PNE2') AND AV.Response = 'Y' THEN '2'
        WHEN AV.Query = 'PN20' AND AV.Response = 'Y' THEN '3'
        WHEN AV.Query = 'PN4' AND AV.Response = 'Y' THEN '4'
      ELSE '5'
         END AS [PStatus],

    CASE   
        WHEN O.Order IN ('DO2','FL25','VACHP') THEN '1'
        WHEN AV.Query = 'FL1' AND AV.Response = 'Y' THEN '2'
            WHEN AV.Query = 'REF' AND AV.Response = 'Y' THEN '3'
        WHEN AV.Query IN ('FL2','FL6','NEU.G','HE.B') AND AV.Response = 'Y' THEN '4'
        WHEN AV.Query = 'NOA' AND AV.Response = 'Y' THEN '6'
    ELSE '5'
    END AS [IStatus]

FROM AData AS AD 

        INNER JOIN AVisit AS AV
         ON AD.Visit = AV.Visit
      AND AV.QueryID IN ('PNE1','PNE2','PN20','PN4','FL1','REF','FL2','FL6','NEU.G','HE.B','NOA')

        LEFT JOIN Order AS O
     ON AD.Visit = O.Visit
         AND O.Order IN ('NEI2','DO2','FL25','VACHP');

Answer 1

您希望状态为group by吗？

SELECT AcctNum,
       (CASE WHEN O.Order = 'NEI2' THEN '1'
             WHEN AV.Query IN ('PNE1','PNE2') AND AV.Response = 'Y' THEN '2'
             WHEN AV.Query = 'PN20' AND AV.Response = 'Y' THEN '3'
             WHEN AV.Query = 'PN4' AND AV.Response = 'Y' THEN '4'
             ELSE NULL
        END) AS [Pstatus],
       (CASE WHEN O.Order IN ('DO2','FL25','VACHP') THEN '1'
             WHEN AV.Query = 'FL1' AND AV.Response = 'Y' THEN '2'
             WHEN AV.Query = 'REF' AND AV.Response = 'Y' THEN '3'
             WHEN AV.Query IN ('FL2','FL6','NEU.G','HE.B') AND AV.Response = 'Y' THEN '4'
             WHEN AV.Query = 'NOA' AND AV.Response = 'Y' THEN '6'
             ELSE NULL
        END) AS [IStatus]
FROM AData AS AD INNER JOIN
     AVisit AS AV
     ON AD.Visit = AV.Visit 
WHERE AV.QueryID IN ('PNE1', 'PNE2', 'PN20', 'PN4', 'FL1', 'REF', 'FL2','FL6', 'NEU.G','HE.B','NOA') LEFT JOIN
     Order AS O
     ON AD.Visit = O.Visit AND O.Order IN ('NEI2','DO2','FL25','VACHP');
GROUP BY AcctNum, 
       (CASE WHEN O.Order = 'NEI2' THEN '1'
             WHEN AV.Query IN ('PNE1','PNE2') AND AV.Response = 'Y' THEN '2'
             WHEN AV.Query = 'PN20' AND AV.Response = 'Y' THEN '3'
             WHEN AV.Query = 'PN4' AND AV.Response = 'Y' THEN '4'
             ELSE NULL
        END) AS [Pstatus],
       (CASE WHEN O.Order IN ('DO2','FL25','VACHP') THEN '1'
             WHEN AV.Query = 'FL1' AND AV.Response = 'Y' THEN '2'
             WHEN AV.Query = 'REF' AND AV.Response = 'Y' THEN '3'
             WHEN AV.Query IN ('FL2','FL6','NEU.G','HE.B') AND AV.Response = 'Y' THEN '4'
             WHEN AV.Query = 'NOA' AND AV.Response = 'Y' THEN '6'
             ELSE NULL
        END) AS [IStatus];

Answer 2

我已将您的查询修改为group by AcctNum，以及[Pstatus]和[IStatus]的值。

不要相信有可能实现您在示例2中建议的内容 - 即生成SQL分组/合并规则以将行值（3,5）（4,5）（5,2）合并为（3， 2）（4,5）：

示例2：如果客户21具有服务'PN20'，'PN4'和'FL1'则结果应该是

AcctNum  PStatus  IStatus
     21       3        2
     21       4        5

我的建议是将您的数据分组到AcctNum，以及[Pstatus]和[IStatus]的值，因为任何“更多”都需要超出其价值的复杂性：

SELECT
      AcctNum,
      (CASE 
          WHEN O.Order = 'NEI2' THEN '1'
          WHEN AV.Query IN ('PNE1','PNE2') AND AV.Response = 'Y' THEN '2'
          WHEN AV.Query = 'PN20' AND AV.Response = 'Y' THEN '3'
          WHEN AV.Query = 'PN4' AND AV.Response = 'Y' THEN '4'
          ELSE '5'
        END
      ) AS [Pstatus],
      (CASE   
          WHEN O.Order IN ('DO2','FL25','VACHP') THEN '1'
          WHEN AV.Query = 'FL1' AND AV.Response = 'Y' THEN '2'
          WHEN AV.Query = 'REF' AND AV.Response = 'Y' THEN '3'
          WHEN AV.Query IN ('FL2','FL6','NEU.G','HE.B') AND AV.Response = 'Y' THEN '4'
          WHEN AV.Query = 'NOA' AND AV.Response = 'Y' THEN '6'
          ELSE '5'
        END
      ) AS [IStatus]
    FROM AData AS AD 
    INNER JOIN AVisit AS AV ON AD.Visit = AV.Visit AND 
               AV.QueryID IN ('PNE1','PNE2','PN20','PN4','FL1','REF','FL2','FL6','NEU.G','HE.B','NOA')

    LEFT JOIN Order AS O ON AD.Visit = O.Visit AND 
              O.Order IN ('NEI2','DO2','FL25','VACHP');

    GROUP BY AcctNum,
      (CASE 
          WHEN O.Order = 'NEI2' THEN '1'
          WHEN AV.Query IN ('PNE1','PNE2') AND AV.Response = 'Y' THEN '2'
          WHEN AV.Query = 'PN20' AND AV.Response = 'Y' THEN '3'
          WHEN AV.Query = 'PN4' AND AV.Response = 'Y' THEN '4'
          ELSE '5'
        END),
      (CASE   
          WHEN O.Order IN ('DO2','FL25','VACHP') THEN '1'
          WHEN AV.Query = 'FL1' AND AV.Response = 'Y' THEN '2'
          WHEN AV.Query = 'REF' AND AV.Response = 'Y' THEN '3'
          WHEN AV.Query IN ('FL2','FL6','NEU.G','HE.B') AND AV.Response = 'Y' THEN '4'
          WHEN AV.Query = 'NOA' AND AV.Response = 'Y' THEN '6'
          ELSE '5'
        END)

案例陈述逻辑不完全正常

2 个答案: