Question

我现在已经打破了这个问题了一段时间，所以我想我会在这里试一试。

我有以下表格：

quotes(id, quote_version_id, etc for brevity)
quote_versions(id, quote_id, etc)
v2_quote_payments(id, quote_id, amount, etc)
quote_product_items(quote_version_id, amount, discount, price, etc)
quote_freight_items(quote_version_id, amount, price, etc)
quote_service_items(quote_version_id, amount, price, etc)

引用有很多版本，但quote_version_id表示current_version。我需要获得付款超过50％的报价（sum(v2_quote_payments.amount > (total_freights + total_products + total_services)

到目前为止，我有这个，但总和不一致（total_freights等），由于某种原因，我有总和，可能是由于不同的quote_versions？

    SELECT 
        quotes.id as quote_id, 
        quote_versions.id as quote_version,
        sum(v2_op_payments.amount) as total_paid, 
        coalesce(sum(quote_product_items.amount * quote_product_items.price * (1 + (quote_product_items.discount/100))), 0) + 
        coalesce(sum(quote_service_items.amount * quote_service_items.price), 0) +
        coalesce(sum(quote_freight_items.amount * quote_freight_items.price * (1 + (quote_freight_items.discount/100))), 0),
        sum(quote_product_items.amount * quote_product_items.price * (1 + (quote_product_items.discount/100))) as total_prod,
        sum(quote_service_items.amount * quote_service_items.price) as total_serv,
        sum(quote_freight_items.amount * quote_freight_items.price * (1 + (quote_freight_items.discount/100))) as total_freight
    FROM 
        `quotes` 
        INNER JOIN `v2_op_payments` ON `v2_op_payments`.`quote_id` = `quotes`.`id` 
        INNER JOIN `quote_versions` ON `quote_versions`.`quote_id` = `quotes`.`id` 
        INNER JOIN `v2_production_orders` ON `v2_production_orders`.`quote_id` = `quotes`.`id` 
        LEFT OUTER JOIN `quote_product_items` ON `quote_product_items`.`quote_version_id` = `quote_versions`.`id` 
        LEFT OUTER JOIN `quote_freight_items` ON `quote_freight_items`.`quote_version_id` = `quote_versions`.`id` 
        LEFT OUTER JOIN `quote_service_items` ON `quote_service_items`.`quote_version_id` = `quote_versions`.`id` 
        LEFT OUTER JOIN quote_cancellations ON quote_cancellations.quote_id = quotes.id 
    WHERE 
        `quote_cancellations`.`id` IS NULL 
        AND `quote_versions`.`approved` = 1 
        AND (quote_versions.id = quotes.quote_version_id) 
    GROUP BY
        quotes.id

我这样做是为了检查每个报价的总和是否正确计算，然后继续。

其他条件仅检查报价是否已获批准，且报价中没有取消项目。

我在这里缺少什么？

谢谢，

修改

这是架构和查询的sqlfiddle：http://sqlfiddle.com/#!2/23ff06/1

支付超过50％的发票的Sql

0 个答案: