Question

第一次在Powershell v3中尝试自定义对话框。我想在表单中添加一个浏览按钮。我有它所以它显示浏览按钮，但我似乎无法弄清楚我们从OpenFileDialog对象获取文件名并让它出现在objTextBox字段中的部分。我已经研究过，但似乎找不到任何解释这部分过程的文章。

$objTextBox = New-Object System.Windows.Forms.TextBox
$objTextBox.Name = 'Text1' 
$objTextBox.Location = New-Object System.Drawing.Size(10,40) 
$objTextBox.Size = New-Object System.Drawing.Size(260,20) 
$objForm.Controls.Add($objTextBox) 



#File Browser Code.

    $FileBrowser = New-Object System.Windows.Forms.OpenFileDialog -Property @{
        InitialDirectory = [Environment]::GetFolderPath('Desktop')
    }


$browse_button = New-Object system.Windows.Forms.Button
$browse_button.Text = "Choose...."
$browse_button.Location = New-Object System.Drawing.Size(10,75) 
$browse_button.Size = New-Object System.Drawing.Size(100,27) 
$browse_button.Add_Click({[void]$FileBrowser.ShowDialog()})
$objForm.Controls.Add($browse_button)

Answer 1

我想我的处理方式略有不同。我创建了一个显示“浏览文件”对话框并输出字符串的函数（我只是将其保留在手边）。然后为Add_Click设置文本框的值=该函数。类似的东西：

Function Get-FilePath{
[CmdletBinding()]
Param(
    [String]$Filter = "|*.*",
    [String]$InitialDirectory = "C:\")

    [void][System.Reflection.Assembly]::LoadWithPartialName("System.windows.forms")
    $OpenFileDialog = New-Object System.Windows.Forms.OpenFileDialog
    $OpenFileDialog.initialDirectory = $InitialDirectory
    $OpenFileDialog.filter = $Filter
    [void]$OpenFileDialog.ShowDialog()
    $OpenFileDialog.filename
}

$objTextBox = New-Object System.Windows.Forms.TextBox
$objTextBox.Name = 'Text1' 
$objTextBox.Location = New-Object System.Drawing.Size(10,40) 
$objTextBox.Size = New-Object System.Drawing.Size(260,20) 
$objForm.Controls.Add($objTextBox)
$browse_button = New-Object system.Windows.Forms.Button
$browse_button.Text = "Choose...."
$browse_button.Location = New-Object System.Drawing.Size(10,75) 
$browse_button.Size = New-Object System.Drawing.Size(100,27) 
$browse_button.Add_Click({$objTextBox.Text = Get-FilePath -InitialDirectory "$env:UserProfile\Desktop"})
$objForm.Controls.Add($browse_button) 
$browse_button.Text = "Choose...."
$browse_button.Location = New-Object System.Drawing.Size(10,75) 
$browse_button.Size = New-Object System.Drawing.Size(100,27) 
$browse_button.Add_Click({[void]$FileBrowser.ShowDialog()})
$objForm.Controls.Add($browse_button)

将“浏览”对话框中的文件选择文本传输到Powershell中的“文本输入”字段

1 个答案: