假设我有桌子
id name
1 nora
2 mars
3 ven
我在这张桌子上加入了id
id type value
1 clothing shirt
1 clothing pants
1 toys abacus
1 toys legos
...
我如何制作看起来像的东西,
id name clothing toys
1 nora shirt, pants abacus, legos
答案 0 :(得分:2)
如果要将不同的值放入不同的结果列,则简单连接无效。 您需要使用相关子查询:
SELECT id,
name,
(SELECT group_concat(value, ', ')
FROM Table2
WHERE id = Table1.id
AND type = 'clothing'
) AS clothing,
(SELECT group_concat(value, ', ')
FROM Table2
WHERE id = Table1.id
AND type = 'toys'
) AS toys
FROM Table1