Question

我以这种格式在全球范围内拥有数据：

 ^kza("mltab","TAB","Dta",1,1)  =   3341
 ^kza("mltab","TAB","Dta",1,2)  =   "First Name"
 ^kza("mltab","TAB","Dta",1,3)  =   "type1"
 ^kza("mltab","TAB","Dta",1,4)  =   7400.11
 ^kza("mltab","TAB","Dta",2,1)  =   3614
 ^kza("mltab","TAB","Dta",2,2)  =   "Second Name"
 ^kza("mltab","TAB","Dta",2,3)  =   "type2"
 ^kza("mltab","TAB","Dta",2,4)  =   7600.11

我的对象类看起来像这样：

Class Kza.Employees Extends %Persistent [ StorageStrategy = EmpStorage ]
{

    Property num As %Integer; //unique identifier
    Property id As %Integer;
    Property num As %Integer;
    Property name As %String;
    Property type As %String;
    Property pay As %Double;
    Index NewIndex1 On id [ IdKey, PrimaryKey, Unique ];

    <Storage name="EmpStorage">
     <ExtentSize>100000</ExtentSize>
     <SequenceNumber>8</SequenceNumber>
     <SQLMap name="MasterMap">
       <ConditionalWithHostVars></ConditionalWithHostVars>
       <Data name="num">
         <Node>1</Node>
       </Data>
       <Data name="name">
         <Node>2</Node>
       </Data>
       <Data name="pay">
         <Node>4</Node>
       </Data>
       <Data name="type">
         <Node>3</Node>
       </Data>
       <Global>^kza</Global>
       <RowIdSpec name="1">
         <Expression>{L1}</Expression>
         <Field>id</Field>
       </RowIdSpec>
       <Subscript name="1">
         <Expression>"mltab"</Expression>
       </Subscript>
       <Subscript name="2">
         <Expression>"TAB"</Expression>
       </Subscript>
       <Subscript name="3">
         <Expression>"Dta"</Expression>
      </Subscript>
      <Subscript name="4">
         <Expression>{id}</Expression>
      </Subscript>
      <Type>data</Type>
    </SQLMap>
  <StreamLocation>^Kza.EmployeesS</StreamLocation>
  <Type>%CacheSQLStorage</Type>
</Storage>
}

问题在于，如果我这样做

insert into Kza.Employees(id, num, name, pay, type) VALUES(132, 3214, 'Name Second', 89000, 'type5')

结果是：

^kza("mltab","TAB","Dta",1) =   ""
^kza("mltab","TAB","Dta",1,1)   =   3214
^kza("mltab","TAB","Dta",1,2)   =   "Name Second"
^kza("mltab","TAB","Dta",1,3)   =   'type 5'
^kza("mltab","TAB","Dta",1,4)   =   89000

但是我不需要保存第一行，所以如何消除这个节点：

^ kza（＆＃34; mltab＆＃34;，＆＃34; TAB＆＃34;，＆＃34; Dta＆＃34;，1）=＆＃34;＆＃34;

Answer 1

尝试制作所需的num，name，type或pay属性（如果有任何不能为null） Caché定义了^ kza（“mltab”，“TAB”，“Dta”，1）节点，因为如果其他4个字段都为null，则存在^ kza（“mltab”，“TAB”，“Dta”， 1）节点定义行的存在。换句话说，如果num，name，type或pay都为null并且未定义^ kza（“mltab”，“TAB”，“Dta”，1），则不会定义该行。

IntersystemsCaché自定义存储持久对象

1 个答案: