function toggle(source) {
checkboxes = document.getElementsByName('options[]');
for (var i = 0, n = checkboxes.length; i < n; i++) {
checkboxes[i].checked = source.checked;
}
}
&#13;
<form class="unsubscribe_form" action="process.php" method="post">
<input type="checkbox" class="unsubscribe-checkbox" name="options[]" id="checkbox-1-1" value="Option1">
<label for="checkbox-1-1"></label>Option 1
<input type="checkbox" class="unsubscribe-checkbox" name="options[]" id="checkbox-1-2" value="Option2">
<label for="checkbox-1-2"></label>Option 2
<input type="checkbox" class="unsubscribe-checkbox" name="options[]" id="checkbox-1-3" value="Option2">
<label for="checkbox-1-3"></label>Option 3
<input type="checkbox" class="unsubscribe-checkbox" name="options[]" id="checkbox-1-4" value="Option3">
<label for="checkbox-1-4"></label>Option 4
<input type="checkbox" class="unsubscribe-checkbox" name="options[]" id="checkbox-1-5" value="Option3">
<label for="checkbox-1-5"></label>Option 5
<input type="checkbox" class="unsubscribe-checkbox" id="checkbox-1-6" value="All" onClick="toggle(this)" />
<label for="checkbox-1-6"></label>All
<br>
<input type="submit" name="formSubmit" value="Unsubscribe" />
</form>
&#13;
当我选中All复选框时,它当然会标记所有复选框,但是当我取消选中一个复选框后,仍然会选中All复选框。这应该是未选中的。我应该如何使用JS?
答案 0 :(得分:0)
您需要为每个复选框添加onchange
个事件处理程序,并检查内部是否有&#34;全部&#34;应选中复选框(选中所有复选框)或取消选中(至少取消选中一个)。例如:
var checkboxes = [].slice.call(document.getElementsByName('options[]')),
allCheckbox = document.querySelector('input[value="All"]');
checkboxes.forEach(function(checkbox) {
checkbox.onchange = function() {
if (!this.checked) {
allCheckbox.checked = false;
}
else {
var checked = checkboxes.filter(function(check) {
return check.checked;
});
if (checked.length === checkboxes.length) {
allCheckbox.checked = true;
}
}
};
});
function toggle(source) {
for (var i = 0, n = checkboxes.length; i < n; i++) {
checkboxes[i].checked = source.checked;
}
}
&#13;
<form class="unsubscribe_form" action="process.php" method="post">
<input type="checkbox" class="unsubscribe-checkbox" name="options[]" id="checkbox-1-1" value="Option1">
<label for="checkbox-1-1"></label>Option 1
<input type="checkbox" class="unsubscribe-checkbox" name="options[]" id="checkbox-1-2" value="Option2">
<label for="checkbox-1-2"></label>Option 2
<input type="checkbox" class="unsubscribe-checkbox" name="options[]" id="checkbox-1-3" value="Option2">
<label for="checkbox-1-3"></label>Option 3
<input type="checkbox" class="unsubscribe-checkbox" name="options[]" id="checkbox-1-4" value="Option3">
<label for="checkbox-1-4"></label>Option 4
<input type="checkbox" class="unsubscribe-checkbox" name="options[]" id="checkbox-1-5" value="Option3">
<label for="checkbox-1-5"></label>Option 5
<input type="checkbox" class="unsubscribe-checkbox" id="checkbox-1-6" value="All" onClick="toggle(this)" />
<label for="checkbox-1-6"></label>All
</form>
&#13;
请注意,为了使用方便的数组方法,我将复选框集合转换为带有[].slice.call
的数组。可以使用简单的for循环。
答案 1 :(得分:0)
我建议如下:
function toggle() {
// getting a reference to all the 'name="option[]" elements:
var options = document.getElementsByName('options[]'),
// a reference to the 'all' checkbox:
all = document.getElementById('checkbox-1-6');
// if the changed checkbox is the 'all':
if (this === all) {
// we iterate over all the options checkboxes (using
// Array.prototype.forEach()):
Array.prototype.forEach.call(options, function(checkbox) {
// and we set their checked property to the checked property
// state of the 'all' checkbox:
checkbox.checked = all.checked;
});
} else {
// otherwise we set the 'all' checkbox to the state of
// the Boolean returned by Array.prototype.every(),
// which returns true if all checkboxes evaluate to
// the condition within the function, otherwise false:
all.checked = Array.prototype.every.call(options, function(checkbox) {
return checkbox.checked;
});
}
}
// getting a NodeList of all the elements of 'class="unsubscribe-checkbox"':
var options = document.querySelectorAll('.unsubscribe-checkbox');
// iterating over them, again with Array.prototype.forEach()
// and assigning a change event-listener, which will execute the
// name function:
Array.prototype.forEach.call(options, function(opt) {
opt.addEventListener('change', toggle);
});
function toggle() {
var options = document.getElementsByName('options[]'),
all = document.getElementById('checkbox-1-6');
if (this === all) {
Array.prototype.forEach.call(options, function(checkbox) {
checkbox.checked = all.checked;
});
} else {
all.checked = Array.prototype.every.call(options, function(checkbox) {
return checkbox.checked;
});
}
}
var options = document.querySelectorAll('.unsubscribe-checkbox');
Array.prototype.forEach.call(options, function(opt) {
opt.addEventListener('change', toggle);
});
&#13;
<form class="unsubscribe_form" action="process.php" method="post">
<input type="checkbox" class="unsubscribe-checkbox" name="options[]" id="checkbox-1-1" value="Option1">
<label for="checkbox-1-1"></label>Option 1
<input type="checkbox" class="unsubscribe-checkbox" name="options[]" id="checkbox-1-2" value="Option2">
<label for="checkbox-1-2"></label>Option 2
<input type="checkbox" class="unsubscribe-checkbox" name="options[]" id="checkbox-1-3" value="Option2">
<label for="checkbox-1-3"></label>Option 3
<input type="checkbox" class="unsubscribe-checkbox" name="options[]" id="checkbox-1-4" value="Option3">
<label for="checkbox-1-4"></label>Option 4
<input type="checkbox" class="unsubscribe-checkbox" name="options[]" id="checkbox-1-5" value="Option3">
<label for="checkbox-1-5"></label>Option 5
<input type="checkbox" class="unsubscribe-checkbox" id="checkbox-1-6" value="All" />
<label for="checkbox-1-6"></label>All
<br>
<input type="submit" name="formSubmit" value="Unsubscribe" />
</form>
&#13;
您可能会注意到我已从“所有&#39;”中删除了onClick
属性。复选框,优先于不显眼的JavaScript,其中事件处理程序是通过JavaScript本身分配的(通常用于更容易维护的代码,因为要传递给给定函数的参数在代码本身中分配,而不是在HTML中单独更新。
参考文献: