我有两个清单:
List A List B
ID FirstName WorkingID ID FirstName WorkingID
5 John Null 5 John 1
9 Patrick Null 9 Patrick 2
16 Ryan Null 16 Ryan 3
我想使用LINQ比较这些列表,如果两个列表中的ID相等,我想在第一个列表A列表中设置WorkingID。 感谢。
答案 0 :(得分:5)
也是这样的:
A.ForEach(c => c.WorkingID = B.Where(m => m.ID == c.ID).Select(s => s.WorkingID).FirstOrDefault());
完整来源:
public class Test
{
public int ID;
public int? WorkingID;
}
class Program
{
static void Main(string[] args)
{
var A = new List<Test>()
{
new Test { ID = 5, WorkingID = null },
new Test { ID = 9, WorkingID = null },
new Test { ID = 16, WorkingID = null },
new Test { ID = 18, WorkingID = null }
};
var B = new List<Test>()
{
new Test { ID = 5, WorkingID = 1 },
new Test { ID = 9, WorkingID = 2 },
new Test { ID = 16, WorkingID = 3 }
};
A.ForEach(c => c.WorkingID = B.Where(m => m.ID == c.ID).Select(s => s.WorkingID).FirstOrDefault());
}
}
答案 1 :(得分:2)
试试这个:
listA.Where(a => listB.Any(b => a.ID == b.ID))
.ToList()
.ForEach(a => a.WorkingID = listB.First(b => b.ID == a.ID).WorkingID);
答案 2 :(得分:1)
var query = from a in lista
join b in listb on a.ID equals b.ID
where b.WorkingID != null
select new {a, b};
foreach (var item in query)
{
item.a.WorkingID = item.b.WorkingID;
}
很简单。
答案 3 :(得分:1)
您可以尝试这样的事情(不是纯粹的LINQ方法):
foreach(var item in listA)
{
var itemInB = listB.FirstOrDefault(x=>x.ID==item.ID);
if(itemInB!=null)
item.WorkingID = itemInB.WorkongID
}
答案 4 :(得分:1)
这是一种方法,假设一个类结构如下:
class MyItem
{
public int ID { get; set; }
public string FirstName { get; set; }
public int WorkingID { get; set; }
}
您可以加入匹配ID的第二个列表:
var list1 = new List<MyItem>() {
new MyItem() { ID = 5, FirstName = "John" },
new MyItem() { ID = 9, FirstName = "Patrick" },
new MyItem() { ID = 16, FirstName = "Ryan" },
};
var list2 = new List<MyItem>() {
new MyItem() { ID = 5, FirstName = "John", WorkingID = 1 },
new MyItem() { ID = 9, FirstName = "Patrick", WorkingID = 2 },
new MyItem() { ID = 16, FirstName = "Ryan", WorkingID = 3 },
};
var mergedList = from item1 in list1
join item2 in list2
on item1.ID equals item2.ID
select new MyItem() { ID = item1.ID, FirstName = item1.FirstName, WorkingID = item2.WorkingID };
答案 5 :(得分:1)
我认为使用Join
然后循环遍历列表会更有效率。以下几乎与Florian Schmidinger提供的答案相同:
A.AsEnumerable().Join(B.AsEnumerable(), a => a.ID, b => b.ID, (a, b) => new { a, b })
.ToList().ForEach(obj => { obj.a.WorkingID = obj.b.WorkingID; });