Question

如何制作如下内容的任何想法？

让我们：

a = {'p': 1, 'r': 2}
b = {'p': 1, 'r': 3}

这是一个简化的条目，但是想象一下有更常见的键值对，因此目标是使定义更小，更易读。是否有任何方法可以对其进行别名，以便我可以编写例如：

m = ('p': 1)  # note this does not work
a = {m, 'r': 2}
b = {m, 'r': 3}

这是我的问题的混淆版本：

what = {
        sr: [{'los_angels': mg, 'sg': sg, 'ua': boston, 'new_york': seattle},
                    {'los_angels': mg, 'sg': sg, 'new_york': seattle},
                    {'los_angels': mg, 'ua': boston, 'new_york': seattle},
                    {'los_angels': mg, 'new_york': seattle},
                    {'los_angels': mg, 'ua': boston, 'new_york': seattle, 'apple': 'IS'},
                    {'los_angels': mg, 'new_york': seattle, 'apple': 'IS'}],
        as: [{'los_angels': mg, 'ua': boston, 'new_york': seattle}, {'los_angels': mg, 'new_york': seattle},
                {'los_angels': mg, 'ua': boston, 'new_york': seattle, 'apple': 'IS'},
                {'los_angels': mg, 'new_york': seattle, 'apple': 'IS'}],
        dd: [{'los_angels': 'orange', 'new_york': seattle},
                    {'los_angels': 'orange', 'new_york': seattle, 'ua': boston},
                    {'los_angels': 'orange', 'new_york': seattle, 'apple': 'IS'},
                    {'los_angels': 'orange', 'new_york': seattle, 'ua': boston, 'apple': 'IS'}],
        a: [{}, {'ua': boston}, {'new_york': seattle}, {'new_york': seattle, 'ua': boston}],
        b: [{}, {'ua': boston}, {'new_york': seattle}, {'new_york': seattle, 'ua': boston}],
        c: [{}, {'ua': boston}, {'new_york': seattle}, {'new_york': seattle, 'ua': boston}],
        d: [{}, {'ua': boston}, {'new_york': seattle}, {'new_york': seattle, 'ua': boston}],
        e: [{}, {'ua': boston}, {'new_york': seattle}, {'new_york': seattle, 'ua': boston}],
        f: [{}, {'ua': boston}, {'new_york': seattle}, {'new_york': seattle, 'ua': boston}],
        g: [{}],
        h: [{}],
        i: [{}, {'los_angels': mg}],
    }

所以我正在寻找一些方法来制作＆＃39; los_angels＆＃39; orange＆＃39; orange＆＃39;部分，＆＃39; ub＆＃39;：波士顿小：）

Answer 1

您不能使用预定义的键值对，不能，但还有其他选项：

您可以定义基本词典，然后用它更新a和b：

m = {'p': 1}
a = {'r': 2}
a.update(m)
b = {'r': 3}
a.update(m)

您可以使用dict()函数将两个词典合并为一个新词典，或者添加其他键作为关键字参数：
```
m = {'p': 1}
a = dict(m, r=2)
b = dict(m, r=3)
```
这需要其他键（例如r）为valid Python identifiers。您可以使用**语法来解决该限制：
```
m = {'p': 1}
a = dict(m, **{'r': 2})
b = dict(m, **{'r': 3})
```
现在r可以是任何字符串。

您可以将键和值定义为单独的变量，并使用：

m_key, m_value = 'p', 1
a = {m_key: m_value, 'r': 2}
b = {m_key: m_value, 'r': 3}

将第二个选项应用于混淆样本：

la_orange = {'los_angels': 'orange'}

what = {
        sr: [{'los_angels': mg, 'sg': sg, 'ua': boston, 'new_york': seattle},
                    {'los_angels': mg, 'sg': sg, 'new_york': seattle},
                    {'los_angels': mg, 'ua': boston, 'new_york': seattle},
                    {'los_angels': mg, 'new_york': seattle},
                    {'los_angels': mg, 'ua': boston, 'new_york': seattle, 'apple': 'IS'},
                    {'los_angels': mg, 'new_york': seattle, 'apple': 'IS'}],
        as: [{'los_angels': mg, 'ua': boston, 'new_york': seattle}, {'los_angels': mg, 'new_york': seattle},
                {'los_angels': mg, 'ua': boston, 'new_york': seattle, 'apple': 'IS'},
                {'los_angels': mg, 'new_york': seattle, 'apple': 'IS'}],
        dd: [dict(la_orange, new_york=seattle),
                    dict(la_orange, new_york=seattle, ua=boston),
                    dict(la_orange, new_york=seattle, apple='IS'),
                    dict(la_orange, new_york=seattle, ua=boston, apple='IS')],
        a: [{}, {'ua': boston}, {'new_york': seattle}, {'new_york': seattle, 'ua': boston}],
        b: [{}, {'ua': boston}, {'new_york': seattle}, {'new_york': seattle, 'ua': boston}],
        c: [{}, {'ua': boston}, {'new_york': seattle}, {'new_york': seattle, 'ua': boston}],
        d: [{}, {'ua': boston}, {'new_york': seattle}, {'new_york': seattle, 'ua': boston}],
        e: [{}, {'ua': boston}, {'new_york': seattle}, {'new_york': seattle, 'ua': boston}],
        f: [{}, {'ua': boston}, {'new_york': seattle}, {'new_york': seattle, 'ua': boston}],
        g: [{}],
        h: [{}],
        i: [{}, {'los_angels': mg}],
    }

如果需要组合多个这样的预定义词典，可以创建辅助函数：

def combine_dicts(*d, **kw):
    """Combine dictionaries into one.

    Keys in later dictionaries override those in earlier dictionaries, with
    keyword arguments being applied last.

    """
    return reduce(lambda d1, d2: dict(d1, **d2), d + (kw,))

然后将其用于：

a = combine_dicts(base1, base2, {'some non-identifier key': 42}, r=3)

Answer 2

您只需对代码进行最小程度的更改：

m=(('p',1),)
a=dict(m, r=2)
b=dict(m, r=3)

定义dict条目Python

2 个答案: