列出注册“CS-204”课程和“CS-102”课程
的学生姓名table1:enroll
student id , code, grade
table2:student
student id ,name ,bdate,address
.................................. 我试着
select student.name,enrol.code from student,enrol where code='CS-204' or code='CS-102'
答案 0 :(得分:0)
你必须加入两个表:
select student.name,enrol.code
from student join enrol on student.student_id=enrol.student_id
where code='CS-204' and student.student_id in (
select student.name,enrol.code
from student join enrol on student.student_id=enrol.student_id
where code='CS-102'
)
答案 1 :(得分:0)
您需要加入表格
SELECT s.name, e.code
FROM student s
INNER JOIN enroll e ON s.student_id = e.student_id
WHERE e.code='CS-204' OR e.code='CS-102'
答案 2 :(得分:0)
您需要在WHERE子句中再添加一个参数:
SELECT student.name, enroll.code
FROM student, enroll
WHERE (student.student_id=enroll.student_id) AND (enroll.code='CS-204' OR enroll.code='CS-102')
答案 3 :(得分:0)
您可以尝试这样做。
Select student.name from student join enroll
on student.student_id = enroll.student_id where
enroll.code in ('CS-204','CS-102');
答案 4 :(得分:0)
您也可以通过这种方式获得两门课程的学生姓名:
SELECT b.name as student_name
FROM enroll a, student b
WHERE (a.student_id=b.student_id) AND (a.code='CS-204' or a.code='CS-102'`)