删除php中的空格后获取最后四个字符

Question

我有一个字符串4345 5666 7768 6555我想在获取最后四个字符之后首先删除它的空格，如何使用PHP？

Answer 1

使用此代码

$str = "4345 5666 7768 6555";

$str = str_replace(" ","",$str);
echo $str = substr($str,-4);

Answer 2

尝试 -

$str = str_replace(" ", "", $str); // replace spaces
echo substr($str, -4); // get last four characters

Answer 3

$str = "4345 5666 7768 6555";

$str = str_replace(" ","",$str);
echo $str =trim(substr($str,-4));