Question

我必须对表运行查询以获取每个特定字段值的总和。

rechargedate    originid
------------------------
2015-02-02      3
2015-02-02      3
2015-02-02      1
2015-02-02      1
2015-02-02      3
2015-02-02      2
2015-02-01      2
2015-02-01      3
2015-02-01      1
2015-02-01      1
2015-02-01      2

查询结果应该是：

rechargedate    orig1   orig2   orig3
-------------------------------------
2015-02-02      2       1       3
2015-02-01      2       2       1

如何使用MS SQL 2008实现这一目标？

Answer 1

使用PIVOT。查看this以了解PIVIOT

中的SQL SERVER.

SELECT rechargedate, 
       [1] AS orig1,
       [2] AS orig2,
       [3] AS orig3 
FROM #TEST
PIVOT(COUNT(originid) FOR originid IN([1],[2],[3])) AS Piv
ORDER BY rechargedate DESC

Answer 2

您可以使用条件聚合：

CREATE TABLE #temp(
    RechargeDate    DATE,
    OriginID        INT
)
INSERT INTO #temp VALUES
('2015-02-02', 3),('2015-02-02', 3),('2015-02-02', 1),
('2015-02-02', 1),('2015-02-02', 3),('2015-02-02', 2),
('2015-02-01', 2),('2015-02-01', 3),('2015-02-01', 1),
('2015-02-01', 1),('2015-02-01', 2);

SELECT
    RechargeDate,
    orig1 = SUM(CASE WHEN OriginID = 1 THEN 1 ELSE 0 END),
    orig2 = SUM(CASE WHEN OriginID = 2 THEN 1 ELSE 0 END),
    orig3 = SUM(CASE WHEN OriginID = 3 THEN 1 ELSE 0 END)
FROM #temp
GROUP BY RechargeDate
ORDER BY RechargeDate DESC

DROP TABLE #temp

<强> RESULT

RechargeDate orig1       orig2       orig3
------------ ----------- ----------- -----------
2015-02-02   2           1           3
2015-02-01   2           2           1

Answer 3

最简单的方法是使用CASE语句创建所需的列，然后进行求和，例如，

SELECT rechargedate,
     SUM(CASE WHEN originid = 1 THEN 1 ELSE 0 END) AS orig1,
     SUM(CASE WHEN originid = 2 THEN 1 ELSE 0 END) AS orig2,
     SUM(CASE WHEN originid = 3 THEN 1 ELSE 0 END) AS orig3
FROM {your_table}
GROUP BY rechargedate
ORDER BY rechargedate DESC

如何按字段的行和特定值汇总

3 个答案: