Question

我有一系列活动记录对象，我想按特定顺序排序。

可能有0到5个结果：

[#<Milestone id: 657708, event_id: 2426, event_type: "Part", data_type: "setup_required", date_at: "2014-11-13 06:27:05", user_id: 1003>, #<Milestone id: 657707, event_id: 2426, event_type: "Part", data_type: "setup_ready", date_at: "2014-11-13 06:27:05", user_id: 1003>]

这是我要按其排序的数组。

status = %w[setup_ready setup_required bom_processing pending_approval part_live]

我想针对数组元素对data_type进行排序。

所以在这种情况下，我的结果将是：

[#<Milestone id: 657707, event_id: 2426, event_type: "Part", data_type: "setup_ready", date_at: "2014-11-13 06:27:05", user_id: 1003>, #<Milestone id: 657708, event_id: 2426, event_type: "Part", data_type: "setup_required", date_at: "2014-11-13 06:27:05", user_id: 1003>]

建议后的代码：

milestones = Milestone.where(event_id: params[:id])
status = %w[setup_ready setup_required bom_processing pending_approval part_live]
@part_milestones = milestones.sort_by {|m| status.index(m.data_type)}

milestones = [#<Milestone id: 657708, event_id: 2426, event_type: "Part", data_type: "setup_required", date_at: "2014-11-13 06:27:05", user_id: 1003>, #<Milestone id: 657707, event_id: 2426, event_type: "Part", data_type: "setup_ready", date_at: "2014-11-13 06:27:05", user_id: 1003>]

@part_milestones = [#<Milestone id: 657708, event_id: 2426, event_type: "Part", data_type: "setup_required", date_at: "2014-11-13 06:27:05", user_id: 1003>, #<Milestone id: 657707, event_id: 2426, event_type: "Part", data_type: "setup_ready", date_at: "2014-11-13 06:27:05", user_id: 1003>]

通过添加to_s：

解决

@part_milestones = milestones.sort_by {| m | status.index（m.data_type.to_s）}

Answer 1

假设milestones包含Milestone ActiveRecord对象的集合：

milestones = Milestone.all
status = %w[setup_ready setup_required bom_processing pending_approval part_live]

sorted_milestones = milestones.sort_by {|m| status.index(m.data_type)}

如果状态列表中不存在任何里程碑data_types，则应将它们排序到数组的末尾。

针对数组安排活动记录结果

1 个答案: