如何从2个表中选择信息？

Question

我试图从两个表中获取数据：

$con = getDbConnect();
$edit = $_GET['edit'];

if (mysqli_connect_errno($con)) {
    "Failed to connect to MySQL: " . mysqli_connect_error();
} else {
    $result = mysqli_query($con, "SELECT * FROM admininfo where email='" . $edit . "'");
    $results = mysqli_query($con, "SELECT * FROM adminaccount where email='" . $edit . "'");

while ($admininfo = mysqli_fetch_array($result, $results)) {

Answer 1

无论您选择多少个表格，都可以使用单个查询，例如

SELECT a.*, b.* FROM table1 a, table2 b where a.id = ? AND b.id = ?

然后，您从结果中获取所需内容，请查看docs。

- 当然，不要使用select *。