Question

我正在尝试建立用户删除链接。我用这个djnago-tables2。在应该有删除链接的地方有水平线。

class UsersListTable(BaseTable):
    user = tables.Column(
        order_by=('user__last_name', 'user__first_name'),
        accessor='user.get_full_name',
        verbose_name=_('Employee')
    )

    delete_link = tables.LinkColumn('deleteUser', args=[A('pk')])

    class Meta(BaseTable.Meta):
        model = MyModel
        fields = ('country', 'name', 'delete_link')
        empty_text = _('No users')

我的观点：

class DeleteUser(DeleteView):
    model = MyModel
    template_name = "templates/list_of_users.html"
    success_url = reverse_lazy('myapp:base')

    def get_object(self, queryset=None):
        obj = super(DeleteUser, self).get_object()
        return obj

    def get_success_url(self):
        return reverse('base')

我的网址：

url(r'^delete/(?P<pk>\d+)/$', views.DeleteUser.as_view(), name='deleteUser'),

Answer 1

您可以使用TemplateColumn：

#tables.py:
TEMPLATE = '''
<a href="{% url 'deleteUser' record.pk %}">delete</a>
'''

class UsersListTable...
   ....
   delete_link = tables.TemplateColumn(TEMPLATE)

另一个选项是render_FOO metod （https://django-tables2.readthedocs.org/en/latestindex.html?highlight=render_foo）

删除链接LinkColumn不能正常工作django-tables2

1 个答案: