$("#nomlabo").select2({
//tags:true,
ajax: {
dataType: "json",
url: "includes/labotags.php",
results: function (data) {
//alert(data[1]);
return {
results: data
};
}
},
tags: ["result1", "result2", "result3", "result4"],
maximumSelectionSize: 1
});
嗨我想将数据结果中的值放入“标签”中, 这怎么可行?
答案 0 :(得分:0)
我已经改变了代码来从php而不是jquery:
$("#nomlabo").select2({
tags: [
<?php
$results =array();
if ($stm = $mysqli->prepare("SELECT * FROM laboratoire")) {
$stm->execute();
$stm->store_result();
$stm->bind_result($id,$nom_labo,$id_nationalite);
while ($stm->fetch()) {
echo '"'.$nom_labo.'",';
}
}
?>
],
maximumSelectionSize: 1
});