所以我有3种不同（但它们有一些相似之处），我想将这些结合起来进行一些计算
Array
(
[0] => Array
(
[0] => Agent
[1] => Answered
[2] => Missed
[3] => Contribution
[4] => Per Hour
[5] => Total Ring Time
[6] => Mean Ring Time
[7] => Total Talk Time
[8] => Mean Talk Time
[9] => Total Wrap Time
[10] => Mean Wrap Time
[11] => Total Session Time
[12] => Mean Session Time
[13] => Number of Sessions
[14] => % Util
[15] => Agent Hang-Ups
[16] => Caller Hang-Ups
[17] => Agent Hang-Ups Percent
[18] => Caller Hang-Ups Percent
)
[1] => Array
(
[0] => Amber
[1] => 16
[3] => 2.0%
[4] => 0.2
[5] => 28.6
[6] => 1.8
[7] => 1861.1
[8] => 116.3
[9] => 0.0
[10] => 0.0
[11] => 234862.2
[12] => 3403.8
[13] => 69.0
[14] => 0.8%
[15] => 10
[16] => 6
[17] => 62.5%
[18] => 37.5%
)
[2] => Array
(
[0] => Amie
[1] => 106
[3] => 13.5%
[4] => 3.0
[5] => 721.7
[6] => 6.8
[7] => 12268.0
[8] => 115.7
[9] => 0.0
[10] => 0.0
[11] => 127011.0
[12] => 6350.5
[13] => 20.0
[14] => 9.7%
[15] => 54
[16] => 52
[17] => 50.9%
[18] => 49.1%
)
)
数组2
Array
(
[0] => Array
(
[0] => Agent
[1] => Answered
[2] => Missed
[3] => Contribution
[4] => Per Hour
[5] => Total Ring Time
[6] => Mean Ring Time
[7] => Total Talk Time
[8] => Mean Talk Time
[9] => Total Wrap Time
[10] => Mean Wrap Time
[11] => Total Session Time
[12] => Mean Session Time
[13] => Number of Sessions
[14] => % Util
[15] => Agent Hang-Ups
[16] => Caller Hang-Ups
[17] => Agent Hang-Ups Percent
[18] => Caller Hang-Ups Percent
)
)
阵列3
[0] => Array
(
[0] => Agent
[1] => Answered
[2] => Missed
[3] => Contribution
[4] => Per Hour
[5] => Total Ring Time
[6] => Mean Ring Time
[7] => Total Talk Time
[8] => Mean Talk Time
[9] => Total Wrap Time
[10] => Mean Wrap Time
[11] => Total Session Time
[12] => Mean Session Time
[13] => Number of Sessions
[14] => % Util
[15] => Agent Hang-Ups
[16] => Caller Hang-Ups
[17] => Agent Hang-Ups Percent
[18] => Caller Hang-Ups Percent
)
[1] => Array
(
[0] => (7312
[1] => 1
[3] => 0.0%
[4] => 459.8
[5] => 0.0
[6] => 0.0
[7] => 0.4
[8] => 0.4
[9] => 0.0
[10] => 0.0
[11] => 7.8
[12] => 2.6
[13] => 3.0
[14] => 5.5%
[15] => 1
[17] => 100.0%
[18] => 0.0%
)
[2] => Array
(
[0] => Amber
[1] => 414
[2] => 9
[3] => 9.3%
[4] => 6.3
[5] => 1880.1
[6] => 4.4
[7] => 65209.8
[8] => 157.5
[9] => 240.4
[10] => 0.6
[11] => 234862.2
[12] => 3403.8
[13] => 69.0
[14] => 27.8%
[15] => 290
[16] => 124
[17] => 70.0%
[18] => 30.0%
)
所以在这个例子中我有3个数组，都有相同的第一个初始数组。但是这些阵列的大小可能不同，并且它们可能不会共享相同的人。 人们也可以在不同的地方，即。
Array 1 : Common -> Amber -> Amie
Array 2 : Common ->
Array 3 : Common -> 7312 -> Amber ->Amie
现在最终的数组看起来像
Array 4 : Common -> 7312 -> Amber -> Amie
所有数组中的所有值也应该组合在一起，即：
Amber 1st array / 1st value : 16
Amber 2nd array / 2nd value : 414
Amber final array value : 414 + 16 = 430
希望我已经提出了问题。
答案 0 :(得分：1)
基本上，您总结了所有信息，删除标题。然后使用信息合并重建一个新数组。
//merge all arrays, remove the first element, it is headers.
$my_total_array = array_merge(
array_splice($array1,1),
array_splice($array2,1),
array_splice($array3,1)
);
$myagents = array();
foreach($my_total_array as $agent){
if(!isset($myagents[$agent[0]])){
//Never met the agent, add them.
$myagents[$agent[0]] = $agent;
}else{
//We already seen the agent, do maths.
$myagents[$agent[0]][1]+=$agent[1];
//TODO: Apply consolidation rules for other fields.
}
}
//Put the headings back at the beggining.
array_unshift($myagents,$array1[0]);
print_r($myagents);
我希望这会有所帮助。
编辑：来自PHP文档
将一个或多个数组的元素合并在一起，以便显示值 一个附加到前一个的末尾。它返回 结果数组。
如果输入数组具有相同的字符串键，则后面的值 对于该键，将覆盖前一个。但是，如果是数组 包含数字键，后面的值不会覆盖原始 值，但会附加。