现在尝试各种技术并不占上风,任何人都可以对此有所了解。
//Google search -------------------
app.get("/google/:name", function (req, res) {
var term = req.params.name;
var searchTerm = function (search, callback) {
var options = {
hostname: "ajax.googleapis.com",
path: "/ajax/services/search/web?v=1.0&q="+ search + ""
};
var gsaReq = http.get(options, function (response) {
var completeResponse = '';
response.on('data', function (chunk) {
completeResponse += chunk;
});
response.on('end', function() {
outputResult(completeResponse);
});
}).on('error', function (e) {
console.log('problem with request: ' + e.message);
});
}(term, outputResult);
function outputResult(result){
console.log(result);
res.send(result);
// res.send('hello world');
};
});
如果res.send()
发送hello world
而不是我的回拨的result
,尽管结果是字符串,这可以正常工作吗?有什么想法吗?
如果上述内容没有意义,则下面的代码会被简化(没有回调)且res.send()仍然会失败..?
如果没有回调,res.send就无法工作 - 啊哈:
app.get("/google/:name", function (req, res) {
var term = req.params.name;
var searchTerm = function (search) {
var options = {
hostname: "ajax.googleapis.com",
path: "/ajax/services/search/web?v=1.0&q="+ search + ""
};
var gsaReq = http.get(options, function (response) {
var completeResponse = '';
response.on('data', function (chunk) {
completeResponse += chunk;
});
response.on('end', function() {
res.send(completeResponse);
});
}).on('error', function (e) {
console.log('problem with request: ' + e.message);
});
}(term);
});