Question

我正在创建一个基于此脚本的脚本。但是当我在结果上运行它时，如果几个月不相同，它会删除比日期更新的文件。

Linux shell script for delete old files from ftp

＆＃34;删除02-02-2015＆＃34;这是我今天创建的备份

#!/bin/bash
# get a list of directories and dates from ftp and remove directories older than ndays
ftpsite="hostname"
ftpuser="user"
ftppass="pass"
putdir="/full"

ndays=15


# work out our cutoff date
MM=`date --date="$ndays days ago" +%b`
DD=`date --date="$ndays days ago" +%d`


echo removing files older than $MM $DD

# get directory listing from remote source
listing=`ftp -i -n -p $ftpsite <<EOMYF
user $ftpuser $ftppass
binary
cd $putdir
ls
quit
EOMYF
`
lista=( $listing )

# loop over our files
for ((FNO=0; FNO<${#lista[@]}; FNO+=9));do
  # month (element 5), day (element 6) and filename (element 8)
  # echo Date ${lista[`expr $FNO+5`]} ${lista[`expr $FNO+6`]}          File: ${lista[`expr $FNO+8`]}

  # check the date stamp
  if [ ${lista[`expr $FNO+5`]}=$MM ];
   then
    if [[ ${lista[`expr $FNO+6`]} -lt $DD ]];
    then
      # Remove this file
      echo "Removing ${lista[`expr $FNO+8`]}";
      ftp -i -n -p $ftpsite <<EOMYF2
      user $ftpuser $ftppass
      binary
      cd $putdir
      mdelete ${lista[`expr $FNO+8`]}/*
      rmdir ${lista[`expr $FNO+8`]}
      quit
      EOMYF2
   fi
  fi
done

result =＆gt; 删除早于1月18日的文件删除02-02-2015

Answer 1

这条线似乎是错误的，因为它总是如此：

if [ ${lista[`expr $FNO+5`]}=$MM ];

你应该在“=”周围写一些空格。正确的形式是：

if [ ${lista[`expr $FNO+5`]} = $MM ];

[ ]是bash内置的，其参数将传递给“test”命令。 [ asd = "$qwe" ]相当于：test "asd" "=" "$qwe"

FTP删除超过X天的目录

1 个答案: