Question

我正在开发一个向服务器发送大量数据的应用程序。现在我想使用volley将一组params发送到php页面。但是我无法发送它。

将params添加为数组的代码。

String[] arr =new String[7];
    for(int i=1;i<=7;i++)
    {
        arr[i]="questionId_"+i+"_"+"ans_"+i;

    }
    HashMap<String ,String[]> params=new HashMap<String, String[]>(7);
    params.put("params", arr);

向服务器发出请求的代码

RequestQueue que=Volley.newRequestQueue(this);

     final ProgressDialog dialog = new ProgressDialog(HealthMyHistory.this);
     dialog.setTitle("Please Wait");
     dialog.setMessage("Sending Data");
     dialog.setCancelable(false);
     dialog.show();


    CustomJobjectRequest jsObjRequest = new CustomJobjectRequest(Method.POST, url, params, new Response.Listener<JSONObject>() {

                @Override
                public void onResponse(JSONObject response)
                {
                    dialog.dismiss();



                }
            }, new Response.ErrorListener() {

                @Override
                public void onErrorResponse(VolleyError response) {

                    dialog.dismiss();
                    Toast.makeText(getApplicationContext(), "Unable to Send Data!"+" "+response.toString(), Toast.LENGTH_SHORT).show();
                }
            });
    que.add(jsObjRequest);

}



Problem is in CustomJobjectRequest there is no constructor available of type in which Hashmap accepts string & array as argument.How to do it ?

代码或CustomJsonObjectRequest

 package com.example.healthcoach.data;

import java.io.UnsupportedEncodingException;
import java.util.HashMap;
import java.util.Map;

import org.json.JSONException;
import org.json.JSONObject;

import com.android.volley.NetworkResponse;
import com.android.volley.ParseError;
import com.android.volley.Request;
import com.android.volley.Response;
import com.android.volley.Response.ErrorListener;
import com.android.volley.Response.Listener;
import com.android.volley.toolbox.HttpHeaderParser;


public class CustomJobjectRequest extends Request<JSONObject>{

    private Listener<JSONObject> listener;
    private Map<String, String> params;

    public CustomJobjectRequest(String url, Map<String, String> params,
              Listener<JSONObject> reponseListener, ErrorListener errorListener) {
          super(Method.POST, url, errorListener);
          this.listener = reponseListener;
          this.params = params;
    }

    public CustomJobjectRequest(int method, String url, Map<String, String> params,
              Listener<JSONObject> reponseListener, ErrorListener errorListener) {
          super(method, url, errorListener);
          this.listener = reponseListener;
          this.params = params;
      }

  public CustomJobjectRequest(int post, String url,
            HashMap<String, String[]> params2, Listener<JSONObject> listener2,
            ErrorListener errorListener) {
        // TODO Auto-generated constructor stub
    }

@Override
  protected Map<String, String> getParams() throws com.android.volley.AuthFailureError {
    return params;
  };

  @Override
  protected void deliverResponse(JSONObject response) {
      listener.onResponse(response);
  }

  @Override
  protected Response<JSONObject> parseNetworkResponse(NetworkResponse response) {
       try {
              String jsonString = new String(response.data,
                      HttpHeaderParser.parseCharset(response.headers));
              return Response.success(new JSONObject(jsonString),
                      HttpHeaderParser.parseCacheHeaders(response));
          } catch (UnsupportedEncodingException e) {
              return Response.error(new ParseError(e));
          } catch (JSONException je) {
              return Response.error(new ParseError(je));
          }
  }

}

Answer 1

使用

HashMap<String ,String> params=new HashMap<String, String>(7);
for(int i=1;i<=7;i++)
{
    params.put("params_"+i, arr[i]);
}

<{1>}类中的

因为当前您在CustomJobjectRequest类的Map中使用String类型作为值，但在创建CustomJobjectRequest类的对象时发送String[]类型

修改：

要将单个参数中的所有值发送到服务器使用CustomJobjectRequest。使用所有键值创建一个json对象：

JSONObject

发送服务器端的所有值get JSONObject jsonObject=new JSONObject(); for(int i=1;i<=7;i++) { arr[i]="questionId_"+i+"_"+"ans_"+i; jsonObject.put("params_"+i,arr[i]); } HashMap<String ,String> params=new HashMap<String, String>(); params.put("params",jsonObject.toString());并转换为JSON对象并迭代以获取所有值

Answer 2

使用

    Map<String, String> postParam = new HashMap<>();
    int i=0;
    for(String object: friendIds){
        postParam.put("friendIds["+(i++)+"]", object);
        // you first send both data with same param name as friendnr[] ....  now send with params friendnr[0],friendnr[1] ..and so on
    }

这项工作对我来说，希望对你有用。

Answer 3

使用google json Library制作json数组。

 compile 'com.google.code.gson:gson:2.6.2'

这段代码是将json数组放在请求的主体中

private void sendTokenToServer(final String jsonArrayString) {
        String tag_string_req = "string_req";
        String url = Const.SEND_TOKEN_TO_SERVER;


        final StringRequest strReq = new StringRequest(Request.Method.POST,
                url, new Response.Listener<String>() {

            @Override
            public void onResponse(String response) {
                Log.d(TAG, response.toString());
                hideProgressDialog();
            }
        }, new Response.ErrorListener() {

            @Override
            public void onErrorResponse(VolleyError error) {
                VolleyLog.d(TAG, "Error: " + error.getMessage());
                hideProgressDialog();
            }
        }) {
            @Override
            public Map<String, String> getHeaders() throws AuthFailureError {
                Map<String, String> header = new HashMap<>();
                header.put("Content-Type", "application/json; charset=utf-8");
                return header;
            }


            @Override
            public String getBodyContentType() {
                return "application/json; charset=utf-8";
            }

            @Override
            public byte[] getBody() throws AuthFailureError {
                try {
                    return jsonArrayString.getBytes("utf-8");
                } catch (UnsupportedEncodingException e) {
                    e.printStackTrace();
                }
                return null;
            }

        };
        AppController.getInstance().addToRequestQueue(strReq, tag_string_req);
    }

Answer 4

第1步

制作json param

 Map<String, String> jsonParams = new HashMap<>();

第2步

make set或Arraylist为什么设置或arraylist因为不需要固定lenth

  private Set<String>  arr;
  for(int i=1;i<=7;i++)
    {
        arr[i]="questionId_"+i+"_"+"ans_"+i;
        arr.add("params_"+i,arr[i]);
    }

步骤3将set object作为字符串传递

 if (arr!= null) {
       jsonParams.put("param", arr.toString());
                  }

如何在android中使用volley发送params数组

4 个答案: