Question

我需要为销售业绩生成每周报告

-------------------------------------------------- -------
用户星期一星期二星期五星期五星期六星期六太阳总计
-------------------------------------------------- -------
Naven 25 25 30 25 20 20 0 145
Ajay 15 35 20 25 20 20 0 135

我正在使用经典的asp

例如：

Select username , salesdate , salesamt 
from sales ...... 
group by username

Answer 1

您可以将聚合函数（例如SUM）与CASE条件组合在一起，以获得您想要的报告。

例如：

SELECT USERNAME,
SUM(CASE WHEN WEEKDAY(SALESDATE)=0 THEN SALESAMT ELSE 0 END) AS MON,
SUM(CASE WHEN WEEKDAY(SALESDATE)=1 THEN SALESAMT ELSE 0 END) AS TUE

FROM SALES
GROUP BY USERNAME;

Answer 2

创建表格测试

create table `test` (
    `day` datetime ,
    `val` int (11),
    `user` varchar (768)
); 
insert into `test` (`day`, `val`, `user`) values('2012-01-01 00:00:00','465',NULL);
insert into `test` (`day`, `val`, `user`) values('2012-01-02 00:00:00','896',NULL);
insert into `test` (`day`, `val`, `user`) values('2015-01-26 11:37:07','678','Ajay');
insert into `test` (`day`, `val`, `user`) values('2015-01-26 11:37:07','324','Naven    ');
insert into `test` (`day`, `val`, `user`) values('2015-01-27 11:37:14','74','Ajay');
insert into `test` (`day`, `val`, `user`) values('2015-01-25 11:37:14','65','Naven    ');
insert into `test` (`day`, `val`, `user`) values('2015-01-25 11:37:14','35','Ajay');
insert into `test` (`day`, `val`, `user`) values('2015-02-01 11:35:59','12','Naveen');
insert into `test` (`day`, `val`, `user`) values('2015-02-01 11:37:07','23','Ajay');
insert into `test` (`day`, `val`, `user`) values('2015-01-30 11:36:40','34','Naven    ');
insert into `test` (`day`, `val`, `user`) values('2015-01-30 11:36:40','56','Naven    ');
insert into `test` (`day`, `val`, `user`) values('2015-01-31 11:36:32','12','Ajay');
insert into `test` (`day`, `val`, `user`) values('2015-01-30 11:36:40','13','Ajay');
insert into `test` (`day`, `val`, `user`) values('2015-01-28 11:36:46','14','Naven    ');
insert into `test` (`day`, `val`, `user`) values('2015-02-01 11:37:07','10','Pankaj');
insert into `test` (`day`, `val`, `user`) values('2015-02-01 11:37:07','10','Pankaj');
insert into `test` (`day`, `val`, `user`) values('2015-01-27 11:37:14','20','Naven    ');
insert into `test` (`day`, `val`, `user`) values('2015-01-29 11:37:36','10','Naven    ');

在欲望查询之下

SELECT DAYOFWEEK(DAY) AS sr ,DATE_FORMAT(DAY, '%a') DAY, SUM(val),USER, DAY FROM test
WHERE DAY >= CURDATE() - INTERVAL DAYOFWEEK(CURDATE())+6 DAY
AND DAY < CURDATE() - INTERVAL DAYOFWEEK(CURDATE())-1 DAY
GROUP BY DAY,USER
ORDER BY sr;

每周报告的SQL

2 个答案: