Question

我正在使用ASP.NET MVC项目，该项目使用XML文件作为数据源。我在显示虚拟财产的属性方面遇到了问题。

首先，我有3个模型类

播放器：

public class Player
{
    [Required]
    public String clubName { get; set; }
    [Required]
    public String id { get; set; }
    [Required]
    public int number { get; set; }
    [Required]
    public String name { get; set; }
    [Required]
    public String position { get; set; }
    [Required]
    public DateTime dateOfBirth { get; set; }
    [Required]
    public string placeOfBirth { get; set; }
    [Required]
    public double weight { get; set; }
    [Required]
    public double height { get; set; }
    [Required]
    public String description { get; set; }
    [Required]
    public String imageLink { get; set; }
    [Required]
    public Boolean status { get; set; }

    public virtual ICollection<PlayerAchievement> achievements { get; set; }
}

成就

public class Achievement
{
    [Key]
    public String name { get; set; }

    [Required]
    public String imageLink { get; set; }

    public virtual ICollection<PlayerAchievement> playerAchievements { get; set; }

    public Achievement()
    {
        this.name = null;
        this.imageLink = null;
    }

    public Achievement(String name, String imageLink)
    {
        this.name = name;
        this.imageLink = imageLink;
    }
}

和Player_Achievement类：

public class PlayerAchievement
{
    [Key]
    public String playerId { get; set; }

    [Required]
    public String achievementName { get; set; }

    [Required]
    public int number { get; set; }

    public virtual Player player { get; set; }

    public virtual Achievement achievement { get; set; }

    public PlayerAchievement()
    {
        this.playerId = null;
        this.achievementName = null;
        this.number = 0;

    }

    public PlayerAchievement(int number, String playerId, String achievementName)
    {
        this.playerId = playerId;
        this.achievementName = achievementName;
        this.number = number;
    }
}

我还有3个类的存储库，下面是PlayerAchievement：

public class PlayerAchievementRepository : IPlayerAchievementRepository
{
    public List<PlayerAchievement> allPlayerAchievements;
    private XDocument playerAchievementData;

    public PlayerAchievementRepository()
    {
        //Code get all player_achievement in xml file
    }

    public IEnumerable<PlayerAchievement> GetPlayerAchievementsByPlayerID(String id)
    {
        return allPlayerAchievements.FindAll(item => item.playerId.Equals(id));
    }
}

现在。我想看看球员的成就列表。所以在PlayerAchievementsController的Index动作中，我写了这段代码：

public ActionResult Index(String id)
{
    return View(_repository.GetPlayerAchievementsByPlayerID(id));
}

但是，“索引”视图仅显示图像链接和名称的PlayerAchievement数和空值。我不知道为什么它可以获得1个属性的值而对其他人来说是不可能的。

索引视图部分代码：

<table class="table">
<tr>
    <th>
        @Html.DisplayNameFor(model => model.achievement.imageLink)
    </th>
    <th>
        @Html.DisplayNameFor(model => model.number)
    </th>
    <th></th>
</tr>

@foreach (var item in Model) {
<tr>
    <td>
        @Html.DisplayFor(modelItem => item.achievement.imageLink)
    </td>
    <td>
        @Html.DisplayFor(modelItem => item.number)
    </td>
    <td>
        @Html.ActionLink("Edit", "Edit", new { id=item.playerId }) |
        @Html.ActionLink("Details", "Details", new { id=item.playerId }) |
        @Html.ActionLink("Delete", "Delete", new { id=item.playerId })
    </td>
</tr>

在GitHub上查看我的项目：https://github.com/quyetnv8893/PlayerManagement

Answer 1

我从git hub获得了您的代码副本，但稍有变化，请将AchievementRepository.cs第39行代码上的代码更改为

achievementData.Descendants("achievements").FirstOrDefault().Add(new XElement("achievement",
                new XElement("name", achievement.name), new XElement("imageLink", achievement.imageLink)));

正如您之前的代码创建了无效的xml标记层次结构。

Answer 2

问题解决：我没有从PlayerAchievement 读取相关数据，因此PlayerAchievement中的Achievement属性当前为null。为解决此问题，此代码已在PlayerAchievement的索引操作中更新

public ActionResult Index(String id)
{   
    private IAchievementRepository _achievementRepository = new AchievementRepository();         
    var playerAchievements = _repository.GetPlayerAchievementsByPlayerID(id)
            .Where(achievement => achievement.PlayerID.Equals(id));
    foreach (var achievement in playerAchievements)
    {
        achievement.Achievement = _achievementRepository.GetAchievementByName(achievement.AchievementName);
    }
    return View(playerAchievements.ToList());
}

与使用dbContext.Include（）

相同

属性的值未在视图中显示

2 个答案: