Question

我有一个有桌子的SQLite数据库：

table: import_info
   Columns: First_Name, Last_Name, Payroll_ID, ... other columns not used

tabel employees
   Columns: name, employee_num

我想从第一个表格中选择唯一名称和payroll_id，然后选择name和employee_num。

如果我在SQLite Manager中选择表并运行：

SELECT DISTINCT Last_Name || ' ' || First_Name AS name, Payroll_ID 
AS employee_num 
FROM import_info

我完美地得到了结果。但如果我尝试：

INSERT INTO employees (name, employee_num)
SELECT DISTINCT Last_Name || ' ' || First_Name AS name, Payroll_ID 
AS employee_num 
FROM import_info

我一无所获。没有错误，没有任何反应。

Answer 1

您可以提供以下值：

INSERT INTO employees(name, employee_num, created_at, updated_at)
    SELECT DISTINCT Last_Name || ' ' || First_Name AS name, Payroll_ID,
           datetime('now'), datetime('now')
    FROM import_info

但是，我很惊讶，遗漏这些值并不会导致错误。或许有些东西可以抑制错误。

SQLite Manager INSERT INTO失败但不产生错误

1 个答案: