在一行代码中查找特定的Char，忽略SED中的空格

Question

我刚接触SED，我一直在四处寻找答案！我几乎拥有它，但无法弄明白。

____= a tab or space  

示例文字：

This is sample text - hello.   
______-this is what I want the script to detect only  
Not the - in this one   
______-Just this one 

我的脚本

/[^tab]\+-/ {  
s/$/ \\\\/  
}

输出

This is sample text - hello. //  
____-this is what I want the script to detect only //  
Not the - in this one //  
____-Just this one //  

所需输出

This is sample text - hello.  
____-this is what I want the script to detect only //  
Not the - in this one  
____-Just this one //  

我希望我的脚本查看第一个字符是否为 - （忽略空格/制表符），如果是，则添加空格和//

Answer 1

通过sed，

$ sed '/[^[:blank:]]\+-/s/$/ \/\//' file
This is sample text - hello.
______-this is what I want the script to detect only //
Not the - in this one
______-Just this one //