Question

我想在Python应用程序中使用trakt.tv api进行个人使用，但我无法弄清楚如何处理身份验证。

这是通过OAuth完成的，我正在使用google推荐的回调之一（urn：ietf：wg：oauth：2.0：oob）。从API网站，我应该首先进行授权步骤（我获得一个授权代码），然后将此代码交换为access_token。

我尝试通过从我的浏览器粘贴验证代码来进行交换部分，并且我确实获得了access_token，但是在尝试进行经过身份验证的请求时它仍然提供了403代码。

这是我的代码：

    values = """
  {
    "code": #pasted from browser#,
    "client_id": "#client_id#",
    "client_secret": "#client_secret#",
    "redirect_uri": "urn:ietf:wg:oauth:2.0:oob",
    "grant_type": "authorization_code"
  }
"""

headers = {
    'Content-Type': 'application/json'
}
request = Request('https://api.trakt.tv/oauth/token', data=values, headers=headers)
response_body = json.load(urlopen(request))
token = response_body['access_token'] # token received (checked by print)
headers = {
    'Content-Type': 'application/json',
    'Authorization': 'Bearer %s' % token,
    'trakt-api-version': '2',
    'trakt-api-key': '#client_id#'
}
request = Request('https://api.trakt.tv/sync/watched/movies', headers=headers)
response_body = urlopen(request).read()
print response_body

这会引发以下异常

Traceback (most recent call last):
  File "/Users/luisafonsocarvalho/Documents/Auto Downloader/downloader.py", line 81, in <module>
    response_body = urlopen(request).read()
  File "/usr/local/Cellar/python/2.7.8_1/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 127, in urlopen
    return _opener.open(url, data, timeout)
  File "/usr/local/Cellar/python/2.7.8_1/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 410, in open
    response = meth(req, response)
  File "/usr/local/Cellar/python/2.7.8_1/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 523, in http_response
    'http', request, response, code, msg, hdrs)
  File "/usr/local/Cellar/python/2.7.8_1/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 448, in error
    return self._call_chain(*args)
  File "/usr/local/Cellar/python/2.7.8_1/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 382, in _call_chain
    result = func(*args)
  File "/usr/local/Cellar/python/2.7.8_1/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 531, in http_error_default
    raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 403: Forbidden

任何帮助都会非常感激，因为我似乎有点失落。

编辑：

如果我第二次运行该代码，使用相同的值，我会获得401代码。怎么了？

OAuth供个人使用（trakt.tv）

0 个答案: