我是android编程的新手,并且还在了解它的概念,我正在构建一个应用程序,它将从在线数据库中获取一些数据并将其存储在ArrayList>输入,然后我将显示数据,
我已成功从数据库中获取数据并在ListView上成功显示,现在我想根据其日期对数据进行排序(在hashmap中存储了一个日期值),
我已经阅读了如何在这些问题中做到这一点:
How to sort data of ArrayList of hashmap on The Basis of Date
我没有真正理解这个概念,但仍然不知道如何使用我当前的代码。希望你能帮我解决我的代码,
这是我的代码:
public class Notification extends Activity {
userSessionManager session;
String Username, clickedId, clickedTitle, toastMessage;
String urlUpdateGroupConfirmation, urlGetNotif;
JSONParser jsonParser;
ProgressDialog pd;
JSONArray jsonArray = null;
private ArrayList<HashMap<String, String>> whatsNew;
@Override
protected void onCreate(Bundle savedInstanceState) {
// TODO Auto-generated method stub
super.onCreate(savedInstanceState);
setContentView(R.layout.notification);
getActionBar().setDisplayShowHomeEnabled(false);
sessionAndDeclaration();
new AttemptParseNotification().execute();
}
private void sessionAndDeclaration() {
// TODO Auto-generated method stub
session = new userSessionManager(getApplicationContext());
HashMap<String, String> user = session.getUserDetails();
Username = user.get(userSessionManager.KEY_USERNAME);
myIP ip = new myIP();
String publicIp = ip.getIp();
String thisPhp = "viewMyNotification.php";
String updateGConf = "doUpdateGroupDetail.php";
urlGetNotif = publicIp + thisPhp;
urlUpdateGroupConfirmation = publicIp + updateGConf;
jsonParser = new JSONParser();
whatsNew = new ArrayList<HashMap<String, String>>();
}
class myMapComparator implements Comparator<Map<String, String>> {
@Override
public int compare(Map<String, String> lhs, Map<String, String> rhs) {
// TODO Auto-generated method stub
DateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
try {
return df.parse(lhs.get("date")).compareTo(
df.parse(rhs.get("date")));
} catch (ParseException e) {
throw new IllegalArgumentException(e);
}
}
}
class AttemptParseNotification extends AsyncTask<Void, Void, Boolean> {
@Override
protected void onPreExecute() {
// TODO Auto-generated method stub
super.onPreExecute();
pd = new ProgressDialog(Notification.this);
pd.setIndeterminate(false);
pd.setCancelable(true);
pd.setMessage("Loading...");
pd.show();
}
@Override
protected Boolean doInBackground(Void... arg0) {
// TODO Auto-generated method stub
int success = 0;
try {
List<NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair("Username", Username));
Log.d("Request!", "Passing Username to server");
JSONObject json = jsonParser.makeHttpRequest(urlGetNotif,
"POST", params);
success = json.getInt("success");
if (success == 1) {
Log.d("Response", "Getting todays");
jsonArray = json.getJSONArray("array");
try {
for (int i = 0; i < jsonArray.length(); i++) {
JSONObject c = jsonArray.getJSONObject(i);
String newId = c.getString("id");
String newType = c.getString("type");
String newTitle = c.getString("title");
String newDisplayed = newTitle + "(" + newType
+ ")";
String newDate = c.getString("date");
HashMap<String, String> map = new HashMap<String, String>();
map.put("id", newId);
map.put("title", newTitle);
map.put("date", newDate);
map.put("type", newType);
map.put("displayed", newDisplayed);
whatsNew.add(map);
Collections.sort(whatsNew, new myMapComparator());
}
} catch (JSONException e) {
e.printStackTrace();
}
}
} catch (JSONException e) {
e.printStackTrace();
}
return null;
}
@Override
protected void onPostExecute(Boolean result) {
// TODO Auto-generated method stub
super.onPostExecute(result);
pd.dismiss();
if (whatsNew.size() > 0) {
viewNews();
} else {
Toast.makeText(getBaseContext(), "No new notification",
Toast.LENGTH_LONG).show();
}
}
}
public void viewNews() {
// TODO Auto-generated method stub
ListView lv = (ListView) findViewById(R.id.lv_notif);
ListAdapter adapter = new SimpleAdapter(this, whatsNew,
R.layout.notificationlist_item, new String[] { "title", "type",
"date" }, new int[] { R.id.title_notif,
R.id.type_notif, R.id.date_notif });
lv.setAdapter(adapter);
}
}
答案 0 :(得分:2)
我建议使用TreeSet
代替Collections.sort
,
这是粗略的例子,
public static Set<HashMap<String, String>> mySet = new TreeSet<>(new Comparator<HashMap<String, String>>() {
@Override
public int compare(HashMap<String, String> o1, HashMap<String, String> o2) {
DateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
try {
return df.parse(o1.get("date")).compareTo(
df.parse(o2.get("date")));
} catch (ParseException e) {
throw new IllegalArgumentException(e);
} }
});
b / w Collections.sort
和TreeSet
之间的区别在于TreeSet
始终对您的数据进行排序,而Collections.sort()
方法在您调用方法时对其进行排序你的套装。
mySet.add(yourData);
,它将按排序顺序添加。
答案 1 :(得分:1)
在将所有数据添加到“whatsNew”列表的循环之后,您需要调用比较器对列表进行排序。
在“return null”之前将此行添加到“doInBackground”...
Collections.sort(whatsNew, new myMapComparator());
(旁注:您可能已经知道,在Java中,惯例是以大写字母开始一个类名称)