Question

我想要打开文件xml并找到字符串然后替换。但是当替换字符串时只找到两个字符串并替换这是我的代码

var realpath = "~/template/xml/xmlback";
var filePath = Path.Combine(HttpContext.Current.Server.MapPath("~/template/xml/xmltest") + ".xml");
var filePath2 = Path.Combine(HttpContext.Current.Server.MapPath("~/template/xml/xmlback/test2") + ".xml");
DirectoryInfo dir = new DirectoryInfo(Path.Combine(HttpContext.Current.Server.MapPath(realpath)));
foreach (FileInfo files in dir.GetFiles())
{
    files.Delete();
}
string strVal = System.IO.File.ReadAllText(Server.MapPath("~/template/xml/xmltest") + ".xml");
strVal = strVal.Replace("Test1", "amir");
strVal = strVal.Replace("Test2", "amir1");
strVal = strVal.Replace("Test3", "amir2");
strVal = strVal.Replace("Test4", "amir3");
strVal = strVal.Replace("Test5", "amir4");
strVal = strVal.Replace("Test6", "amir5");
File.Copy(Path.Combine(filePath), Path.Combine(filePath2));
System.IO.File.WriteAllText(Server.MapPath("~/template/xml/xmlback/test2") + ".xml", strVal);
ProcessRequest(filePath2, Lcourseid.Text);

我尝试用word打开xml并查看结果pic

Answer 1

我已经解决了我的问题我使用这段代码但与上面的代码没有区别我认为这是一个损坏的文件xml，找不到Test3和Test4，...... 谢谢大家

    Dictionary<string, string> wordsToReplace = new Dictionary<string, string>();
        wordsToReplace.Add("Test1", "amir");
        wordsToReplace.Add("Test2", "amir1");
        wordsToReplace.Add("Test3", "amir3");
        wordsToReplace.Add("Test4", "amir4");
        wordsToReplace.Add("Test5", "amir5");
        wordsToReplace.Add("Test6", "amir6");
        string strVal = System.IO.File.ReadAllText(Server.MapPath("~/template/xml/xmltest") + ".xml");

        foreach (var pair in wordsToReplace)
        {
            //Performs each replacement
            strVal = strVal.Replace(pair.Key, pair.Value);
        }
        File.Copy(Path.Combine(filePath), Path.Combine(filePath2));
        System.IO.File.WriteAllText(Server.MapPath("~/template/xml/xmlback/test2") + ".xml", strVal);
        ProcessRequest(filePath2, Lcourseid.Text);

在文件xml中查找和替换

1 个答案: