如何使用复选框从数据表中选择id

Question

继承我的代码：带有服务器端的HTML从数据库中获取数据。如何使用复选框选项从数据表中获取ID？

<div class="panel-body">
    <div class="table-responsive">

       <table class="table table-striped table-bordered table-hover" id="dataTables-example">
       <thead>
       <tr>
       <h4>
       <th></th> <!-- For checkbox column-->
       <th>ID Number</th>
       <th>Lastname</th>                                          
       <th>Firstname</th>
       <th>Middlename</th>
       <th>Gender</th>
       <th>Course</th>
       <th>Department</th>
       <th>Address</th>
       <th>Contact</th>
       <th>Birthdate</th>
       <th>View</th>
       <th>Events</th>


       </h4>
       </tr>
       </thead>
       <tbody>

       <?php
       include 'pgconnect.php';
       $mydata = mysqli_query($conn,"SELECT * FROM student") or die(mysql_error());
           while($record = mysqli_fetch_assoc($mydata)) 
              { 
                 $id=$record['id'];
         ?>

        <tr>
        <td><input type="checkbox"></td>
        <td class="id"><?php echo  $record['id'] ?></td>
        <td class="lname"><?php echo $record['last_name'] ?></td>
        <td class="fname"><?php echo $record['first_name'] ?></td>
        <td class="mname"><?php echo $record['mid_name'] ?></td>
        <td class="sex"><?php echo $record['gender'] ?></td>
        <td class="course"><?php echo $record['course'] ?></td>
        <td class="dept"><?php echo $record['department'] ?></td>                                             
        <td class="add"><?php echo $record['home_address'] ?></td>
        <td class="contact"><?php echo $record['contact'] ?></td>
        <td class="bdate"><?php echo $record['birthdate'] ?></td>
        <td><a href="records1.php?id="> View Records </a> </td>
        <td> <a  title='Click here to update record.'href='#edit' data-toggle='modal'><i class="fa fa-pencil fa-fw"></i></a>
             <a title='Click here to add record.' href='#'><i class="fa fa-plus fa-fw"></i></a>
             <a title='Click here to delete record.' href='delete.php?del=<?php echo $record['id'] ?>'><i class="fa fa-trash-o fa-fw"></i></a></td>
        </tr>

        <?php
           }
         ?>  
       </tbody> 

  </table>

这是我的剧本：

$(document).ready(function(){
         $('#dataTables-example').dataTable();
    });

我试图获取ID，但它仍然没有用。希望你能帮帮我。

Answer 1

在您的工作中，您将获得表格中的ID。如果你使用jquery，你应该从复选框中获取它，如;

<script>
$(document).ready(function(){
         document.getElementByID("ckmyid").innerHTML;
    });
</script>

注意：在复选框中添加选择器ID，首先说“ckmyid”，所以代码将是这样的：

<input id="ckmyid" type="checkbox" value="<?php echo  $record['id'] ?>">

根据您的结构，如果您想在其中放置ID，可以直接从查看记录链接中的链接抓取它，如;

<td><a href="records1.php?id=<?php echo  $record['id'] ?>"> View Records </a> </td>