我的数据库中有两个表格。用户和user_role。
CREATE TABLE `user` (
`username` varchar(50) NOT NULL,
`password` varchar(255) NOT NULL,
`enable` tinyint(4) NOT NULL DEFAULT '1',
PRIMARY KEY (`username`),
UNIQUE KEY `unique_username` (`username`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1
CREATE TABLE `user_roles` (
`user_role_id` int(11) NOT NULL AUTO_INCREMENT,
`username` varchar(45) NOT NULL,
`ROLE` varchar(45) NOT NULL,
PRIMARY KEY (`user_role_id`),
UNIQUE KEY `uni_username_role` (`ROLE`,`username`),
KEY `fk_username_idx` (`username`),
CONSTRAINT `fk_username` FOREIGN KEY (`username`) REFERENCES `user` (`username`)
) ENGINE=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=latin1
' ROLE'在user_roles中显示用户具有{ROLE_USER,ROLE_ADMIN}
的角色我想使用@RolesAllowed拒绝用户访问某些页面(并授予管理员访问权限),但我不知道如何从数据库获取user_role并将其发送给RolesAllowed。
在Controller中获取user_role并不是一个问题,但我不认为检查每个函数中的用户角色是个好主意。
或者,或许,比使用@RolesAllowed更好的解决方案?
对不起这个愚蠢的问题,这是我第一次看到Spring的5个小时。
答案 0 :(得分:2)
您没有详细介绍您正在构建的应用程序的体系结构,但作为初学者,我可以从我正在构建的应用程序中提供一些示例。我正在使用Spring Boot,JPA,Spring Data和Spring Security。我有类似的要求,并解决了这个问题:
我已经实现了UserDetailsService接口。它用于检索有关尝试登录的用户的信息。当我使用JPA和Spring Data时,服务和模型类看起来像这样(getters,setter和大多数字段为简洁而删除):
@Entity
// in your case this would map to the User table
public class Profile implements UserDetails {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Integer id;
// you should probably use bean validation / jpa to assure uniqueness etc.
private String name;
...
@ElementCollection(fetch = FetchType.EAGER)
private Set<Role> roles = ImmutableSet.<Role> of(new Role("USER"));
...
}
@Embeddable
// in your case this would map to the user_role table
public class Role implements GrantedAuthority {
public final static Role USER = new Role("USER");
public final static Role ADMIN = new Role("ADMIN");
private String authority;
...
}
@Transactional
@Service
public class ProfileService implements UserDetailsService {
private final ProfileRepository profileRepository;
@Autowired
public ProfileService(ProfileRepository profileRepository){
this.profileRepository = profileRepository;
}
public Profile loadUserByUsername(String username) throws UsernameNotFoundException {
Profile profile = profileRepository.findByUsername(username);
// this is the only way to authenticate
if (profile == null) {
throw new UsernameNotFoundException("security.userNotFound");
}
return profile;
}
// you may want to add profile creation etc.
...
}
完成此设置后,我必须配置Spring Security才能使用此服务。我主要使用Java Config,所以配置看起来像。
@Configuration
public class SecurityConfig extends WebSecurityConfigurerAdapter {
@Autowired
private ProfileService profileService;
@Bean
public PasswordEncoder passwordEncoder() {
return new BCryptPasswordEncoder();
}
@Override
protected void configure(AuthenticationManagerBuilder auth)
throws Exception {
auth.userDetailsService(profileService).passwordEncoder(passwordEncoder());
}
@Override
protected void configure(HttpSecurity http) throws Exception {
http.formLogin()
.loginPage("/login")
.permitAll()
.and()
.authorizeRequests()
.antMatchers(HttpMethod.POST, "/**")
.authenticated()
...
// you may want to put more config here
}
}