Question

我刚刚开始为我的python游戏开发课程编写代码。我试图比较元组中的项目和列表中的项目并获得响应。每当我运行代码时，我都会收到元组项不可调用的错误。我将在下面发布代码。如果你知道什么是错的，请帮帮我。谢谢！

pick_up = "Yes"

i = 0

bag = ()

if not bag:
    print("You are empty-handed.")

print("\nYou have found some items")

pick_up = input("\nDo you wish to pick them up? Yes/No")

if pick_up == "Yes":

    print("You have successfully picked up the items!")

    bag = (" Knife ", " Gum ", " Water ",
         " Bandages ", " Toilet Paper ")

    print("\nThese are the items in your bag:")
    print(bag)

if pick_up == "No":
     print("You remain empty handed")

howMany = len(bag)
print ("This is how many items are in your bag:", howMany)

while i < howMany:
    print("\nThis is item:" + str(i) + bag[i])
    i = i + 1

grab = "Yes"
j = 0
inventory = []

print ("\nYou have found some items")

grab = input("\nDo you wish to pick them up? Yes/No")

if grab == "Yes":

    print("You have succesffuly picked up the items!")

    inventory = [" Knife "," Napkins "," A McDonald's Drinking Straw "," A Shoe Lace ", " Banana "]
print("\nThese are the items in your inventory:")

print(inventory)

if grab == "No":
    print("You are empty handed")

howMuch = len(inventory)
print("This is how many items are in your inventory:", howMuch)

while j < howMuch:
    print("\nThis is item:" + str(j) + inventory[j])
    j = j + 1

if inventory[0] == bag("Knife"):
    print("We have a match!")

if inventory[0] != bag( 0 ):
    print ("No like items")

感谢所有帮助！谢谢！

Answer 1

元组用括号实例化，但它们用方括号索引，就像列表一样。使用括号传达＆＃34;呼叫＆＃34;在括号前面带有变量名称的函数，但显然变量名是元组，而不是函数名。这就是为什么你被告知你的元组不可调用，因为它不是，虽然你的代码试图调用它。

检查条件（if）语句并将括号更改为方括号。这是一个常见且可以理解的错误。

Answer 2

这里的问题是你将bag定义为python元组并使用错误的语法访问它。

具体来说，你这样定义：

bag = (" Knife ", " Gum ", " Water "," Bandages ", " Toilet Paper ")

然后你试图像这样访问元组的第一个元素：

bag("Knife")

这是方法或函数调用的语法，因此它抱怨你的元组不可调用。

你可能意味着什么

bag[0]

将访问包元组中的第一项。

我试图比较元组和列表中的项目，但得到一个错误

2 个答案: