Question

我正在制作一个简单的程序，根据所选的单词审查用户输入。

puts "Enter your Text: "
text = gets.chomp.downcase!

puts "Word to censor: "
censor1 = gets.chomp
censor1.downcase!

puts "Second word to censor: "
censor2 = gets.chomp
censor2.downcase!

words = text.split(" ")
words.each do |letter|
  if letter == censor1
    print "CENSORED "
  else
    print words + " "
  end
end

那么，是否可以设置：'if letter == censor1 and censor 2'？

Answer 1

如果您询问（低级）censorX是否包含字符letter：

censor1+censor2.include?(letter)

如果您询问censorX＆＃39}是否包含字符letter：

censor1.include?(letter) && censor1.include?(letter)

如果您询问所有censorX个字符串是否等于字符串letter，那么：

if [censor1, censor2,...].uniq == [letter]
  ...
end

Answer 2

您可以在Array#include?

的帮助下检查数组中是否存在对象

if [censor1, censor2].include?(letter)

代码的简化版本：

puts 'Enter your Text: '
text = gets.chomp.downcase
puts 'Word to censor: '
censor1 = gets.chomp.downcase
puts 'Second word to censor: '
censor2 = gets.chomp.downcase

text.split(' ').each do |word|
  if [censor1, censor2].include?(word)
    print 'CENSORED '                                                                                                                                                                  
  else
    print word + ' '
  end
end

更简单，更好的解决方案String#gsub取代了文本中所有出现的删失字词：

puts 'Enter your Text: '
text = gets.chomp.downcase 
puts 'Word to censor: '
censor1 = gets.chomp.downcase
puts 'Second word to censor: '
censor2 = gets.chomp.downcase

[censor1, censor2].each { |c| text.gsub!(c, 'CENSORED') }
puts text

Ruby：是否可以将if语句==设置为2个变量？

2 个答案: