Question

count = 0

while count ** 2 < snum_:
    print "Using search with increment 1, the root lies between", count,"and", count + 1
    count = count + 1

如何让循环只打印最后一行？

Answer 1

您可以保存要打印的字符串，然后在循环之后将其打印出来：

count = 0
result = ''

while count ** 2 < snum_:
    result = "Using search with increment 1, the root lies between %d and %d" % count, count + 1
    count = count + 1

print result

Answer 2

使用for循环和itertools.count()：

import itertools
for count in itertools.count(1):
    if count**2 >= snum_:
        print "Using search with increment 1, the root lies between %d and %d" % count-1, count
        break

但是一般的想法也可以应用于你的while循环：当count**2 不再小于snum_时，打印并中断。

Answer 3

你可以试试这个：

count = 0

while count < 4:
    print('hi')
    count += 1
else:
    # Replace below string with what you wish.
    print('end')

+=表示count + 1。在else完成后达到while（如果您break循环而不是让它正常完成，则不会打印。

如何在while循环中仅打印最后一行

3 个答案: