Question

我从php＆amp;中获取记录将它们保存在关联数组中。我想创建一个像这样的json格式

{
"contacts": [
    {
            "qid": "c201",
            "question": "what is your name?,

    },
    {
            "qid": "c202",
            "question": "what is your age?

    },
   ]}

我正在使用以下代码来获取php中的数据

 <?
$response = array();
require("dbconfig.php");
$sql_get = 'SELECT qquesid,question FROM qhistory_data';
$retval = mysql_query( $sql_get, $conn );
if(!$retval )
{

            $response["success"] = 0;
            $response["message"]= mysql_error();
            echo json_encode($response);
}
else
{

$num_rows=mysql_num_rows($retval);
if($num_rows>=0)
    {
        $i=0;
    while($row = mysql_fetch_array($retval, MYSQL_ASSOC))
        {
            $result_array[]= $row['question'];
            $result_id[]=$row['qquesid'];

        }

Answer 1

如果你想以你提到的形式获取数组，你必须在执行json_encode之前相应地解析它：

$result = array("contacts" => array());
while($row = mysql_fetch_array($retval, MYSQL_ASSOC)) {
    $result["contacts"][]= array("qid" => $row['qquesid'], "question" =>$row['question']);
}

echo json_encode($result);

将php数组转换为json数组

1 个答案: