Question

我想了解今天，昨天，上周，上个月的客户城市明智。

我想要结果

    city today yesterday lastweek lastmnth
     1     23     2         12         12

我的表结构类似于以下

客户

    c_id  city_id  c_name            currentdate
     1      1       Rama             2015-01-30 09:43:17
     2      1       kavitha          2015-04-30 09:43:17

城市

    city_id   city_name
     1          hyd
     2          Wgl

我尝试了以下。

 select c.c_city, (select count(cr_id)  as lastmonth  from customer 
  where currentdate > DATE(NOW() - INTERVAL 30 DAY) )) from customers as c
  left join cities as ci on c.city_id = ci.city_id group by c.city_id

Answer 1

与此类似：

SELECT city_id as city,
SUM(CASE WHEN LEFT(currentdate,10) = LEFT(NOW(),10) THEN 1 ELSE 0 END) as today,
SUM(CASE WHEN LEFT(currentdate,10) = LEFT(NOW()-INTERVAL 1 DAY,10) THEN 1 ELSE 0 END) as yesterday,
SUM(CASE WHEN currentdate > NOW()-INTERVAL 7 DAY THEN 1 ELSE 0 END) as lastweek,
SUM(CASE WHEN currentdate > NOW()-INTERVAL 30 DAY THEN 1 ELSE 0 END) as lastmnth
FROM customers GROUP BY city_id

对于上周和上个月，我假设你的意思是7天前和30天后。但是，如果您需要上周和上个月的数据（在这种情况下对我没有多大意义），您可能需要重写间隔。

如何得到最近1周，最近1个月，昨天的领域数

1 个答案: